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Rasek [7]
4 years ago
7

△HFM∼△PST

Mathematics
1 answer:
loris [4]4 years ago
6 0

Answer:

The perimeter of △HFM is 50.75 units

Step-by-step explanation:

<u><em>The correct picture of the question in the attached figure</em></u>

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

we have

△HFM∼△PST ----> given problem

step 1

Find the scale factor

Let

z ----> the scale factor

z=\frac{HF}{PS}

substitute the given values

z=\frac{14}{8}=1.75

step 2

Find the perimeter of triangle PST

Remember that the perimeter of a triangle is the sum of its three length sides

P=8+9+12=29\ units

step 3

Find the perimeter of triangle HFM

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

so

The perimeter of triangle HFM is equal to the perimeter of triangle PST multiplied by the scale factor

so

29(1.75)=50.75\ units

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The mean number of words per minute (WPM) read by sixth graders is 97 with a standard deviation of 19 WPM. If 75 sixth graders a
andrey2020 [161]

Answer:

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}};

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 97, \sigma = 19, n = 75, s = \frac{19}{\sqrt{75}} = 2.1939

What is the probability that the sample mean would be greater than 101.63 WPM?

This is 1 subtracted by the pvalue of Z when X = 101.63. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{101.63 - 97}{2.1939}

Z = 2.11

Z = 2.11 has a pvalue of 0.9826.

1 - 0.9826 = 0.0174

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

5 0
3 years ago
The Century club runs the concession stand during football games. They sell snacks and drinks. 50 snacks and 180 drinks will sel
katrin2010 [14]

Answer:

The cost of each drink is $1.5

Step-by-step explanation:

Let us represent

The cost of snacks = x

The cost of drinks = y

50 snacks and 180 drinks will sell for $320

Hence:

50x + 180y = 320....... Equation 1

75 snacks and 100 drinks will sell for $225.

Hence:

75x + 100y = 225....... Equation 2

Combining both Equations together

50x + 180y = 320....... Equation 1

75x + 100y = 225....... Equation 2

Multiply Equation 1 by 75 and Equation 2 by 50 to eliminate x

3750x + 13500y = 24000..... Equation 3

3750x + 5000y = 11250....... Equation 4

Subtract Equation 4 from Equation 3

8500y = 12750

y = 12750/8500

y = $1.5

Therefore, the cost of each drink is $1.5

4 0
3 years ago
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