3 years ago

30 seconds of 2.5 mins in percentage

Mathematics

2 answers:

WARRIOR [948]3 years ago

7 0

Answer:

20%

Step-by-step explanation:

2.5 min =(60×2.5)sec=150 sec

30sec to 150sec=30×100/150=20%

baherus [9]3 years ago

5 0

Answer:

20 %

Step-by-step explanation:

2.5 mins = 150 sec

30 sec of 150 sec in % = 30/150 × 100

= 20 %

You might be interested in

Prove (1+sin/csc-cot)-(1-sin/csc+cot)=2(1+cot)

Aloiza [94]

$\dfrac{1+sin}{csc-cot}-\dfrac{1-sin}{csc+cot}=2(1+cot)\\\\\\\text{Proof from LHS }\rightarrow \text{ RHS}\\\\\dfrac{1+sin}{csc-cot}\bigg(\dfrac{csc+cot}{csc+cot}\bigg)-\dfrac{1-sin}{csc+cot}\bigg(\dfrac{csc-cot}{csc-cot}\bigg)\\\\\\\dfrac{csc+cot+sin csc+sincot}{csc^2-cot^2}+\dfrac{-csc+cot+sincsc-sincot}{csc^2-cot^2}\\\\\\\dfrac{2cot+2sincsc}{csc^2-cot^2}\\\\\\\dfrac{2(cot+sincsc)}{1}\\\\\\2\bigg(\dfrac{cos}{sin}+\dfrac{sin\cdot1}{sin}\bigg)\\\\\\2(cot+1)\\\\\\2(1+cot)=2(1+cot)$