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tigry1 [53]
3 years ago
13

3 divided by what equals 5

Mathematics
1 answer:
Galina-37 [17]3 years ago
6 0

Call "what" by the name ' W '.

You said "3 divided by what equals 5:      3 / W = 5

Multiply each side by ' W ' :                        3        = 5 W

Divide each side by  5 :                             3 / 5   =    W

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PLEASE HELP
sweet [91]
The answer is 10 I just subtracted it so
5 0
3 years ago
If $6000 was expected in sales and only $5100 was attained, what reduced fraction represents sales attained?
ira [324]

The reduced fraction that represents the sales attained is 17/20

<h3>How to determine the fraction?</h3>

The given parameters are:

Expected = $6000

Attained = $5100

The fraction is represented as:

Fraction = Attained/Expected

So, we have:

Fraction = 5100/6000

Divide by 300

Fraction = 17/20

Hence, the reduced fraction is 17/20

Read more about fractions at:

brainly.com/question/1622425

#SPJ1

7 0
2 years ago
Mark rolls a fair dice 36 times. How many times would Mark expect to roll a number greater than 5?​
DochEvi [55]

Answer:

Let X be the number of times a Dice rolls 4.

Expected value is 96/6 = 16.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
QUESTION : how are integers and absolute value used in real world situations? THANK YOU ;)
Rama09 [41]
Integers can be used to describe temperature, currency, and sea level.

Examples:
- A drop of 30 degrees = -30
- 25 meters above sea level = 25
-A 30-dollar deposit = 30

With this said, absolute values can also be used in real world situations.

Absolute value can be applied when it comes to distance, such as how far a object is from you, whether it's in front or behind you.
4 0
3 years ago
In cocker spaniels, solid coat color is dominant over spotted coat color. Suppose a homozygous solid-colored dog is crossed to a
Nana76 [90]

Answer:

0.5781

Step-by-step explanation:

Let 'S' be the dominant allele for solid coat color and 's' be the recessive allele for spotted coat color.

By crossing a homozygous solid-colored dog (SS) with a spotted dog (ss), all of the F1 will present the Ss genotype.

When crossing two F1 dogs, the sample space for F2 is:

F2={Ss,sS,ss,SS}

For each puppy, there is a 1 in 4 chance of having a spotted coat.

The probability that at least one of the three F2 puppies have a spotted coat is 100% minus the probability that none have a spotted coat:

P(ss>0) =1- P(ss=0)\\P(ss>0) =1- (1-\frac{1}{4} )^3\\P(ss>0) = 0.5781

The probability that at least one of the three F2 puppies will have a spotted coat is 0.5781.

4 0
3 years ago
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