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3 years ago

How many times can 1 go into 72

Mathematics

2 answers:

mr_godi [17]3 years ago

5 0

Answer:

$72$ $times$

Step-by-step explanation:

This answer can be found by a very easy method.

72 divided by 1

==> 72

Meaning that if we do 1 * 72, and we get 72, this means that 1 can go into 72, 72 times

Degger [83]3 years ago

3 0

1 can go into 72 72 times

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This table shows a family's monthly budget. What percentage of the budget is allocated for entertainment? Round to the nearest t

lutik1710 [3]

Answer:

A)4.1%

Step-by-step explanation:

First you need to add all the payments together to get your total.

1400+300+150+800+300+150+100+100+150+200=3650

Then you cross multiply and divide to get the percentage.

$\frac{entertainment}{total}$ $\frac{150}{3650}$ = $\frac{x}{100}$

When you cross multiply and divide x≈4.1

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4 years ago

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3 years ago

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Daniel [21]

Answer:

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Step-by-step explanation:

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3 years ago

In 3-10 use the distributive property to find each missing factor

Elanso [62]

The missing factor in the equation is -21

<h3>What is a distributive factor?</h3>

The Distributive Property introduces the multiplication operator an existing mathematical statement that involves the addition operator.

From the complete question, the equation is given as:

$6 \times x= (3 \times 7) + (x \times 7)$

Where x represents the missing factor.

So, we have:

$6x= (21) + (7x)$

Remove brackets

$6x= 21 + 7x$

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Evaluate the like terms

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Divide both sides by -1

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Read more about the distributive property at:

brainly.com/question/2807928

6 0

3 years ago

In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays.Find the probability that he did not hit a bounda

Margarita [4]

Answer:

The probability of NOT hitting a boundary is (4/5).

Step-by-step explanation:

Let E: Be the event of hitting a boundary

now, Probability of any event E = $\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}$

Here, number of favorable outcomes = 6

So, P(E) = $\frac{6}{30} = \frac{1}{5}$

⇒Probability of hitting a six is 1/5

Now, P(E) + P(not E) = 1

So, P(not hitting a boundary ) = 1 - P(hitting a boundary)

= 1 - (1/5) = 4/5

Hence, the probability of NOT hitting a boundary is (4/5).

4 0

3 years ago