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Black_prince [1.1K]
4 years ago
12

Match each expression to its simplified form.

Mathematics
1 answer:
alexandr1967 [171]4 years ago
3 0

Answer:

12-1/2r            =>  (13− 3/ 2 r)−(1−r)

r-13/6             =>  (7r-3/2)-(2/3+6r)

13r+20           =>  (6r+7)+(13+7r)

-12+r               =>  (−8−r)+(2r−4)

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People leaving a movie were randomly asked their age. The results are show below. What graph would best display the data, if you
goldenfox [79]

The graphs to use are box plots, histogram and dot plots

<h3>How to determine the graph?</h3>

From the question, the most important factors are:

  • Shape of distribution
  • Spread of data

Using the box plots, histogram and dot plots, one would see the shape and the spread.

While the stem and leaf plot would show specific data values

Read more about graphs at:

brainly.com/question/24461724

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7 0
2 years ago
Find y when x=7 if y=3 when x=2 <br> Please help
adell [148]
ANSWER: y=10.5

HOW TO SOLVE:

set 3/2 equal to x/7 and then solve for x. To do that, multiply 7x3 to get 21. Then divide 21 by 2 to get the answer.

4 0
4 years ago
Help me please!!!!!!
fomenos
Area of semicircle: pi * r^2/2
r = 9/2 = 4.5
3.14 * 4.5^2 = 63.585/2 = 31.7925
Area of middle section:
Make it a rectangle: L * W
9 * 12 = 108
Area of bottom: L * W
6 * 9 = 54
Now add together: 31.7925 + 108 + 54 = 193.7925, round to nearest hundred
Solution: 193.79 in^2
8 0
3 years ago
PV = nRT<br> solve for R
sukhopar [10]

Answer:

you need to have values to solve for this

Step-by-step explanation:

8 0
4 years ago
Help me answer these questions
Reil [10]

Answer:

See below.

Step-by-step explanation:

1.  x = e^(x/y)   Taking logs:

log x =  x/y

x = y log x

Differentiating:

1 = dy/dx log x +  y * 1/x

dy/dx log x = (1 - y/x)

dy/dx =  (1 - y/x) / log x

dy/dx =  ((x - y)/ x) / log x

dy/dx = (x - y) / x log x)

2.  y^x = e ^(y - x)

Taking logs:

x log y = y - x   --------------(A)

y = x + x logy    --------------(B)

dy/dx = 1 + x * 1/y * dy/dx + 1*logy

dy/dx - dy/dx * x/y = 1 + log y

dy/dx ( (x - y) y))  = 1 + log y

dy/dx = y(1 + log y) / (y - x)

Using (A) and (B) :-

dy/dx =  x(1 + logy)(1 + logy) / x logy          The x's cancel, so:

dy/dx = (1 + logy)^2 / log y

Sorry I have to go right now..

The rest of the answers are  on the re-post of these questions

8 0
3 years ago
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