The graphs to use are box plots, histogram and dot plots
<h3>How to determine the graph?</h3>
From the question, the most important factors are:
- Shape of distribution
- Spread of data
Using the box plots, histogram and dot plots, one would see the shape and the spread.
While the stem and leaf plot would show specific data values
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ANSWER: y=10.5
HOW TO SOLVE:
set 3/2 equal to x/7 and then solve for x. To do that, multiply 7x3 to get 21. Then divide 21 by 2 to get the answer.
Area of semicircle: pi * r^2/2
r = 9/2 = 4.5
3.14 * 4.5^2 = 63.585/2 = 31.7925
Area of middle section:
Make it a rectangle: L * W
9 * 12 = 108
Area of bottom: L * W
6 * 9 = 54
Now add together: 31.7925 + 108 + 54 = 193.7925, round to nearest hundred
Solution: 193.79 in^2
Answer:
you need to have values to solve for this
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
1. x = e^(x/y) Taking logs:
log x = x/y
x = y log x
Differentiating:
1 = dy/dx log x + y * 1/x
dy/dx log x = (1 - y/x)
dy/dx = (1 - y/x) / log x
dy/dx = ((x - y)/ x) / log x
dy/dx = (x - y) / x log x)
2. y^x = e ^(y - x)
Taking logs:
x log y = y - x --------------(A)
y = x + x logy --------------(B)
dy/dx = 1 + x * 1/y * dy/dx + 1*logy
dy/dx - dy/dx * x/y = 1 + log y
dy/dx ( (x - y) y)) = 1 + log y
dy/dx = y(1 + log y) / (y - x)
Using (A) and (B) :-
dy/dx = x(1 + logy)(1 + logy) / x logy The x's cancel, so:
dy/dx = (1 + logy)^2 / log y
Sorry I have to go right now..
The rest of the answers are on the re-post of these questions