Answer:
1) Factor form : 
2) 8 second after launch.
Step-by-step explanation:
The height of the ball (in meters above the ground) t seconds after launch is modeled by
To find the time when ball hit the ground, we need to find the factor form of the given function.
When ball hi the ground, then height of the ball from the ground is 0.
Using zero product property, we get
Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.
Answer:
y = (3/4)x + 2
Step-by-step explanation:
Slope-intercept form is y=mx+b where (x, y) is a point on the linear graph, m is the slope (rise/run), and b is the y-intercept (the y-value at which the graph passes through the y-axis).
Looking at the graph, we can see that the point at which the line crosses the y-axis is (0, 2) which makes it the y-intercept. Thus, the b in the slope-intercept form is 2.
Next, we are looking for the slope of the line. To do this, we can calculate the rise/run of the line by choosing to points on it. Since we already have the point (0, 2), we just need one more.
For example, the point (-4, -1) can be used. The slope can be found by ((y-y)/(x-x)) in which the first y and x values correspond with the first point and that of the second correspond with the second set. So in this case, m = (2-(-1))/(0-(-4)) = 3/4
Plugging in the calculated m and b value in the slope intercept equation, we get y = (3/4)x + 2
I believe the building is 75.5 meters long
Point slope form is just a point and the slope written in the form y-y1 =m (x-x1).
Where x1 and y1 (should be subscripts) are (x1,y1) the point you are given.
So in this case all you must do is plug in the given values:
( y-y1 ) = m ( x-x1 )
( y-4. ) = -1 ( x-2 )
This being your answer
I hope this helps!!
