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Nana76 [90]
3 years ago
13

Really need a definite correct answer on this

Mathematics
1 answer:
cluponka [151]3 years ago
6 0
Third choice is correct hope I helped:3
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The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. This distribution
ankoles [38]

Answer:

a) Normal Distribution

b) 0.146

c) 0.070

Step-by-step explanation:

We are given the following information in the question:

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4

a) \bar{x}: mean number of accidents per week at the intersection during a year (52 weeks)

According to central limit theorem, as the sample size becomes larger, the distribution of mean approaches a normal distribution.

Since we have a large sample, the approximate distribution of \bar{x} is a normal distribution with

\text{Mean} = 2.2\\\text{Standard Deviation} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1.4}{\sqrt{52}} = 0.19

b) P(mean is less than 2)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(x > 610)

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Calculation the value from standard normal z table, we have,  

P(\bar{x} < 2) = 0.146

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P(x < 100)

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Calculation the value from standard normal z table, we have,  

P(x

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