Question

In Seaton Park school, 60% of the boys play baseball and 24% of the boys play baseball and football. What percentage of those that play baseball also play football?

Answer 1

Answer:

$0.4\%$

Step-by-step explanation:

Given: 60% of the boys play baseball and 24% of the boys play baseball and football in Seaton Park School

To find: percentage of those that play baseball also play football

Solution:

Let B denotes boys who play baseball and F denotes boys who play football.

$P(B)=60\%$

$P(F\cap B)=24\%$

Percentage of those that play baseball also play football = $P\left ( F|B \right )=\frac{P(F\cap B)}{P(B)}=\frac{24}{60}=\frac{2}{5}=0.4\%$