Given that,
The camera sights the stadium at a 7 degree angle of depression.
The altitude of the blimp i slide 300 m.
To find,
The line of sight distance from the camera to the stadium.
Solution,
If we consider a right angled triangle. Let x is its hypotenuse i.e. the line of sight distance from the camera to the stadium. Using trigonometry :

So, the line of sight is at a distance of 2461.65 m from the camera to the stadium.
Answer:ok so it is 1 A 2C 3 F 4H
Step-by-step explanation:
Answer:
150, 200, 300
Step-by-step explanation:
sum the parts of the ratio , 3 + 4 + 6 = 13 parts
divide the total by 13 to find the value of one part of the ratio
650 ÷ 13 = 50 ← value of 1 part of the ratio , then
3 parts = 3 × 50 = 150 ← number of sweets Cia gets
4 parts = 4 × 50 = 200 ← number of sweets Mia gets
6 parts = 6 × 50 = 300 ← number of sweets Tia gets
-7n=63
n=-9 is your final answer. Hope it help!