How do you Evaluate the expression when =x−7 and =y2 .<br> 7y-x

Would you rather have 1 of 8 slices from a 10" pizza or 1 of 10 slices from a 14" pizza?

stepladder [879]

1 8 of a pizza you get more

7 0

2 years ago

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If n is an odd integer, which equation can be used

soldi70 [24.7K]

Answer:

3,-1,-5 = -3

Step-by-step explanation:

The 3 odd numbers cannot be all negative ,the result would be less than -3

5 0

3 years ago

The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square kilometers, find the dimensions

Art [367]

Hi there!

Answer:
length = 9 kilometres
Width = 12 kilometres

Let's solve this problem step by step!
To find our answer we need to set up and solve an equation.

Let the length of the rectangle be represented by x.
The width of the rectangle can therefore be expressed by 2x - 6.

The area of a rectangle can be found by using the formula:
A = width × length

Plug in the data from the formula
A = x (2x - 6).

Simplify using rainbow technique.
$x(2x - 6) = 2 {x}^{2} - 6x$

Now we've found the simplified expression that expresses the area of the rectangle. Therefore, we can now set up and start solve the equation.

$2 {x}^{2} - 6x = 108$
Subtract 108

$2 {x}^{2} - 6x - 108 = 0$
Divide by 2.

${x}^{2} - 3x - 54$
$(x - 9)(x + 6) = 0$
Rule AB = 0, gives A is 0 or B is 0.

$x - 9 = 0 \\ x = 9 \\ \\ x + 6 = 0 \\ x = - 6$

The length of the rectangle, which was represented by x, must be 9 (since it cannot be a negative number).

Length
$x = 9$
Width
$2x - 6 = 2 \times 9- 6 = 18 - 6 = 12$

Answer:
length = 9 kilometres
Width = 12 kilometres

~ Hope this helps you!

6 0

3 years ago

A rectangle and a square have the same area. a. The width of the rectangle is w inches. The length of the rectangle is 15 inches

harkovskaia [24]

9514 1404 393

Answer:

a) w(4w-15)

b) w²

c) w(4w -15) = w²

d) w = 5

e) 5 by 5

Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

A = w(4w -15)

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b) If w is the side length, the area of the square is (also) the product of length and width:

A = w²

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c) Equating the expressions for area, we have ...

w(4w -15) = w²

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d) we can subtract the right side to get ...

4w² -15w -w² = 0

3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

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e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

4 0

3 years ago

What property was used on 14k + 2 (3k+5) -5 = 10 to obtain 14k + 6k +10 - 5 =10

Elis [28]

$\boxed{\text{The distributive property}}\\\\\text{In order to solve the equation, you would have to first use the }\\\text{distributive property:}\\\\14k + 2 (3k+5) -5 = 10\\\\\text{Distribute the 2 to the variables inside the parenthesis}\\\\14k+6k+10-5=10\\\\\text{You can see that your outcome matches the equation in the question}\\\\\text{Therefore, the distributive property would be your answer}$

5 0

3 years ago

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How do you Evaluate the expression when =x−7 and =y2 . 7y-x