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Scrat [10]
3 years ago
11

What property was used on 14k + 2 (3k+5) -5 = 10 to obtain 14k + 6k +10 - 5 =10

Mathematics
2 answers:
Elis [28]3 years ago
5 0

\boxed{\text{The distributive property}}\\\\\text{In order to solve the equation, you would have to first use the }\\\text{distributive property:}\\\\14k + 2 (3k+5) -5 = 10\\\\\text{Distribute the 2 to the variables inside the parenthesis}\\\\14k+6k+10-5=10\\\\\text{You can see that your outcome matches the equation in the question}\\\\\text{Therefore, the distributive property would be your answer}

Llana [10]3 years ago
5 0

Answer:

Distributive Property

Step-by-step explanation:

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Parabolas y=−2x^2 and y=2x^2 +k intersect at points A and B that are in the third and the fourth quadrants respectively. Find k
OverLord2011 [107]

Answer:

-25  

Step-by-step explanation:

(1)   y = -2x²

(2) y =   2x² + k     Subtract (1) from (2)

    0 =  4x² + k      Subtract 4x² from each side

    k = -4x²

The parabolas are <em>symmetrical about the y-axis.</em>

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8 0
3 years ago
A college library has five copies of a certain text on reserve. Two copies (1 and 2) are first printings, and the other three (3
sleet_krkn [62]

Answer:

B) Outcomes in A = {3, 4, 5} .

C) Outcomes in B = {5, 15, 25, 125, 215} .

D) Outcomes in C = {3, 4, 5, 23, 24, 25} .

Step-by-step explanation:

We are given that a college library has five copies of a certain text on reserve. From which two copies (1 and 2) are of first printings, and the other three (3, 4, and 5) are of second printings.

Also, it is stated that a student will stop examining the books only when a second printing has been selected.

A) The outcomes in S are :

      <u> Number of outcomes</u>                                 <u>Selection of Outcomes</u>

                  1                                                                          3

                  2                                                                         4

                  3                                                                          5

                  4                                                                         13

                  5                                                                         14

                  6                                                                         15

                  7                                                                         23

                  8                                                                         24

                  9                                                                         25

                 10                                                                         123

                 11                                                                          124

                 12                                                                          125

                 13                                                                          213

                 14                                                                           214

                 15                                                                            215

Here outcome 123 means 1st copy of first printing is examined then 2nd copy of first printing is examined and then 3rd copy of second printing is examined and then the student stops.

B) <em>A denote the event that exactly one book must be examined.</em>

 So, the outcomes in A will be outcome number 1, 2 and 3 corresponding to selection 3, 4 and 5 of second printing because in these outcomes only one book is examined.

Hence, outcomes in A = {3, 4, 5} .

C) <em>B be the event that book 5 is the one selected</em>. It means all those outcomes in which book 5 was last examined. So, the outcomes in B will be outcome number 3, 6, 9, 12, 15 corresponding to selection 5, 15, 25, 125, 215

Hence, outcomes in B = {5, 15, 25, 125, 215} .

D) <em>C be the event that book 1 is not examined</em> which is outcome number 1, 2, 3, 7, 8, 9 corresponding to selection 3, 4, 5, 23, 24, 25 .

Hence, outcomes in C = {3, 4, 5, 23, 24, 25} .

6 0
4 years ago
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