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3 years ago

The cross section of a cylinder taken parallel to the base produces which two dimensional shape

1 answer:

5 0

The base is a circle therefore the shape in parallel will be a circle. If the question had said perpendicular to the base. The answer would be a rectangle.

Does that make sense?

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HW5 Box Plot (grade) Categorical Data 6th grade

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Step-by-step explanation:

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3 years ago

Please help due in 9 minutes

ad-work [718]

Answer:

1. b, 2. d, 3. c, 4. a.

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3 years ago

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Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 9x2 y2 and the p

dolphi86 [110]

The vector function is, r(t) = $\bold{ < t,2t^2,9t^2+4t^4 > }$

Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.

First surface is the paraboloid, $z=9x^2+y^2$

Second equation is of the parabolic cylinder, $y=2x^2$

Now to find the intersection of these surfaces, we change these equations into its parametrical representations.

Let x = t

Then, from the equation of parabolic cylinder, $y=2t^2$ .

Now substituting x and y into the equation of the paraboloid, we get,

$z=9t^2+(2t^2)^2 = 9t^2+4t^4$

Now the vector function, r(t) = <x, y, z>

So r(t) = $\bold{ < t,2t^2,9t^2+4t^4 > }$

Learn more about vector functions at brainly.com/question/28479805

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2 years ago

Which pairs of triangles can be shown to be congruent using rigid motions?

andreyandreev [35.5K]

Two figures are congruent if and only if there exists one or more rigid motions which will map one figure onto the other.

1. Triangles ABC and MNP are not congruent.

2. Triangles ABC and EFG are not congruent

3. Triangles ABC and STU are congruent.

4. Triangles EFG and MNP are congruent.

5. Triangles EFG and STU are not congruent.

6. Triangles STU and MNP are not congruent.

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3 years ago

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A game decreased in price by 2/3. After the reduction it was priced at £13. What was the original price of the game?

Archy [21]

Answer:

$x = 39$

Step-by-step explanation:

Based on the given conditions, write: $x=\frac{13}{1-\frac{2}{3}}$

Find common denominator and write numerators above common denominator: $x=\frac{\frac{13}{3-2} }{3}$

Calculate the sum or difference: $x=\frac{\frac{13}{1} }{3}$

Divide the fraction by multiplying its reciprocal: $x=13*3$

Calculate the product or quotient: $x=39$

Answer: $x=39$

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2 years ago

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