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RUDIKE [14]
3 years ago
5

Help asap please and thanks

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0
Andrew has the right answer for that question
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What is the answer plz help
seropon [69]

Answer:

y = 5x + 4

Step-by-step explanation:

The slope always goes before the x and your y-intercept is plus or minus depending on weather it is positive or negative. Your parent function or standard equations) is y = mx + b, so just plug your variable into there.

6 0
3 years ago
A square has an area of 256 square meters. How long is each side?<br><br> _Meters by _ meters
Lorico [155]
Hello!

First, let's write an equation for the problem. 
\sqrt{256}

Now, all you have to do is solve it. 
\sqrt{256} = 16

Each side is 16 meters. 

I hope this helps!
7 0
3 years ago
Helppppppppppppppppppppppppppppp
evablogger [386]

Answer: 33

Step-by-step explanation:

(f of g)(2) = f(g(2))

g(2) = -2(2) = -4

f(-4) = (-4)^2 - 3(-4) + 5 =

16 - - 12 + 5 =

16 + 17 =

33

7 0
1 year ago
Ron has a bag containing 3 green pears and 4 red pears. He randomly selects a pear then randomly selects another pear, without r
oksian1 [2.3K]
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4 0
3 years ago
HELP ASAP I WILL GIVE BRAINLIEST!!
Alexxx [7]

Consider the function F(x)= x³ +½x² −2x +3. Use calc and algebra to find any and all stationary points on the graph of the function.Precalc need help ASAP

Solution:

the above function has more than one root or more than one solution. The derivative of the function represents the slope of the tangent line to the curve

F(x)= x³ +½x² −2x +3, F'(x) = 3(x3-1)+(1/2)(2)(x2-1)-2(x1-1)+0

F'(x)=3x2+x-2 is the slope of the tangent line

setting the slope =0 and solving the quadratic equations, you find all the

critical points of interest

3x2+x-2=0, solve by factoring (3x-2)(x+1)=0, then 3x-2=0, x= 2/3

and x+1=0, x=-1 substituting these values of x in the original equation

you get the corresponding values of F(x) such that;

F(x)= x³ +½x² −2x +3, F(x)=(2/3)3+1/2(2/3)2-2(2/3)+3

= 8/27+4/18-4/3+3 = 8/27+2/9-4/3+3/1 = 59/27 and the first point is

(2/3, 59/27)

F(x)= x³ +½x² −2x +3, F(x)=(-1)3+1/2(-1)2-2(-1)+3

= -1+1/2+2+3 = 9/2 and the 2nd point is ( -1, 9/2)

these two points represents points where the slope of the tangent line to the curve is 0 and could be either maximum or minimum points

You can also find the y intercepts where x = 0 F(x)= x³ +½x² −2x +3, setting x = 0, y= F(x)=3 and the point ( 0,3) is a y intercept setting y = 0, then x intercepts can be found upon solving the equation x³ +½x² −2x +3 =0

3 0
2 years ago
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