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algol13
4 years ago
5

How do I find the unit rate? $253 for 20 hours

Mathematics
1 answer:
DIA [1.3K]4 years ago
5 0
Divide 253 by 20 to get the unit rate.
We get 12.65
So our unit rate is; $12.65 per hour
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A function LaTeX: f\left(x\right)=\sqrt[3]{x}f ( x ) = x 3 is transformed into the function LaTeX: g\left(x\right)=-\sqrt[3]{x}-
shtirl [24]

Answer:

A reflection in the x-axis, and a vertical translation of 8 units down

Step-by-step explanation:

The given function is

f(x) =  \sqrt[3]{x}

The transformed function is

g(x) =  -  \sqrt[3]{x}  - 8

To see the transformation that occurred, we can rewrite g(x) in terms of f(x).

That is:

g(x) =  - f(x) - 8

Therefore f(x) is reflected in the x-axis and translated 8 units down.

The resulting graph decreases from left to right over its entire domain.

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3 years ago
Solve 5(85) using mental math with the help of distributive properties
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425

Step-by-step explanation:

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3 years ago
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What is 0.2 rounded to the nearest whole number?
REY [17]

Answer:

0

Step-by-step explanation:

since 2 isnt up to 5, it cannot equate to 1

5 0
2 years ago
What is wrong with the following equation: 8 + (6/2) = 17 - 5
Sidana [21]
8+6/2=17-5

We can start by reducing the fraction using basic division.

Remember, numerator divided by denominator.

6 \ 2 = 3.

Rewrite the equation-

8+3=17-5

It doesn’t matter which side of the equal sign you start with, but in this case I started with the right hand.

8+3= 11

Rewrite-

11=17-5

Now subtract.


17-5=12

Write the equality.

11=12.

This is false.

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6 0
3 years ago
The annual interest on a $15,000 $ ⁢ 15,000 investment exceeds the interest earned on an $8000 $ ⁢ 8000 investment by $685 $ ⁢ 6
Eduardwww [97]

Answer:

The interest rate on the $ 8, 000 investment is 9. 657 % = 9.66%

While the interest rate on the $ 15, 000 investment is 10.257% = 10.26%

Step-by-step explanation:

Generally, the formular for calculating simple interest, I is given by

I = (principal x rate x time) / 100

Let the the annual interest on the $8,000 investment be represented as I. While the rate is represented as R

Since the time is 1year, interest on the $8, 000 can be expressed as

I = ( 8000 x R × 1) ÷ 100

I = 8000R/100

I = 80R. ( eqn 1)

Also, let the annual interest on $15,000 investment be K and the rate be V

Since interest on $15, 000 is greater than that of the $8,000 by $685

K = I + 685

Also rate V is 0.6% higher than R

V = (R + 0.6)%

This the interest on the $15, 000 is expressed as

K = ( 15000 × V × 1) ÷ 100 (eqn 2)

Substitute for K and V in eqn 2

That is

I + 685 = ( 15000 x (R + 0.6) x 1) ÷ 100

I + 685 = 15000 (R + 0.6) ÷ 100

I + 685 = 150 (R + 0.6)

Open the bracket

I + 685 = 150R + 15 × 0.6

I + 685 = 150R + 9.

This is the same as

150R + 9 = I + 685. ( eqn 3)

Substitute eqn 1 into eqn 3

That is put

I = 80R in eqn 3

150R + 9 = 80R + 685

Collect like terms with R to one side

150R - 80 R = 685 - 9

70R = 676

R = 676 ÷ 70

R = 9.657 %

Recall that V = (R + 0.6)%

V = 10.257 %

Thus the interest rate on the $ 8, 000 investment is 9. 657 % = 9.66%

While the interest rate on the $ 15, 000 investment is 10.257% = 10.26%

8 0
3 years ago
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