7x+1 = (1/3)
2x + 2y = 28
Systems of equations.
Solve equation with single variable first.
7x+1 = (1/3) , x = (-2/21)
Substitute the value of x in second equation and solve for y.
2(-2/21) + 2y = 28, y = (296/21)
I’m assuming that isn’t the correct answer because you wrote the first equation incorrectly.
14a^2 - 24a + 7 - (11a^2 + 42a - 6)...distribute the negative thru the parenthesis
14a^2 - 24a + 7 - 11a^2 - 42a + 6 =
3a^2 -66a + 13 <==
Answer:
The work is incorrect.
Step-by-step explanation:
V=lwh
V=(2)(7.5)(13)
V=195
Answer:

and t ∈ [0,2π]
Step-by-step explanation:
The standard equation for circle is:

Comparing our equation with standard

h= 0,
k= 3
r= 4 (as in standard r², so r =√ r²)
Required:
Parametric equations of the circle
Formula:

Putting values of r and h and k we get

As we need to start the object at (4,3)
x(0) = 4 and y(0) = 3
and the period is 2π
As the rotation is starting clock wise we will invert the value of t i.e -t

and t ∈ [0,2π]
Answer:
540 in2
Step-by-step explanation:
18×3=54×10=540