Question

An isosceles triangle has angle measures 50°, 50°, and 80°. The side across from the 80° angle is 10 inches long. How long are the other sides?

Answer 1

Answer: The value of other side is 7.8 inch.

Explanation:

It is given that the isosceles triangle has angle measures 50°, 50°, and 80°. The side across from the 80° angle is 10 inches long.

Let the given length of other equal sides be x.

The side across from the 50° angle is x inches long.

Law of sine,

$\frac{a}{\sin A}= \frac{b}{\sin B} =\frac{c}{\sin C}$

$\frac{x}{\sin (50)}= \frac{10}{\sin (80)}$

$\frac{x}{0.766} =\frac{10}{0.9848}$

$x =\frac{10}{0.9848}\times (0.766)$

$x =7.778229 \approx 7.8$

Therefore, the value of other side is 7.8 inch.

Answer 2

Answer:

7.78 on apex :))))

Step-by-step explanation: