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3 years ago

8

Mark draws one card from a standard deck of 52. he receives $ 0.45 for a diamond, $ 0.60 for a king and $ 0.75 for the king of d

iamonds. how much should he pay for one draw?

1 answer:

Varvara68 [4.7K]3 years ago

6 0

1.80 i think add these amounts together for the answer

You might be interested in

¿Cuál es el máximo común divisor de 160 y 96?

agasfer [191]

Answer:

32

Step-by-step explanation:

The factors of 96 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

The factors of 160 are: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160

Then the greatest common factor is 32.

Hope this helps!

7 0

3 years ago

Chen is bringing fruit and veggies to serve at an afternoon meeting. He spends a total of $28.70 on 5 pints of cut veggies and 7

ololo11 [35]

Given:
total cost : 28.70
cost per pint of fruit : 2.85

Formula:
5v + 7f = 28.70
5v + 7(2.85) = 28.70
5v + 19.95 = 28.70
5v = 28.70 - 19.95
5v = 8.75
5v/5 = 8.75/5

v = 1.75 cost per pint of veggies.

to check:
v = 1.75 ; f = 2.85 ; total cost = 28.70

5v + 7f = 28.70
5(1.75) + 7(2.85) = 28.70
8.75 + 19.95 = 28.70
28.70 = 28.70

7 0

3 years ago

The percentage of titanium in an alloy used in aerospace castings is measured in 51 randomly selected parts. The sample standard

luda_lava [24]

Answer: $0.3849$

Step-by-step explanation:

Given : sample size : n= 51

sample standard deviation : s= 0.46

Significance level : $\alpha=1-0.95=0.05$

Using chi-square distribution, the critical values will be :

$\chi^2_{\alpha/2, n-1}=\chi_{0.025,\ 50}=71.4202$

$\chi^2_{1-\alpha/2, n-1}=\chi_{0.975,\ 50}=32.3574$

Confidence interval for population standard deviation ( $\sigma$ ) :

$\sqrt{\dfrac{s^2(n-1)}{\chi^2_{\alpha/2}}}$

Substitute all the values , we get

$\sqrt{\dfrac{(0.46)^2(50)}{71.4202}}$

Hence, the 95% two-sided confidence interval for σ : $0.3849$

8 0

3 years ago

Completely factor this polynomial:<br> 16x2-25y2

Furkat [3]

$16x^2-25y^2=(4x)^2-(5y)^2=(4x-5y)(4x+5y)$

3 0

3 years ago

The perimeter of a rectangular field is 336 m. If the length of the field is 89 m, what is its width?

exis [7]

The length of the field will be calculated as:
P=2(L+W)
P=376
W=89
thus substituting the values in the equation we get;
376=2(L+89)
376/2=(L+89)
solving for L;
188=L+89
L=188-89
L=99 yards
therefore the length is 99 yards

Hope it helps!

7 0

3 years ago