Answer:
The correct answers are (1) Option d (2) option a (3) option a
Step-by-step explanation:
Solution
(1) Option (d) The statement is false. A diagonalizable matrix must have n linearly independent eigenvectors: what it implies is that a matrix is diagnostic if it has linearity independent vectors.
(2) Option (a) The statement is false. A diagonalizable matrix can have fewer than n eigenvalues and still have n linearly independent eigenvectors: what this implies is that a diagonalizable matrix can have repeated eigenvalues.
(3) option (a) The statement is true. AP = PD implies that the columns of the product PD are eigenvalues that correspond to the eigenvectors of A : this implies that P is an invertible matrix whose column vectors are the linearity independent vectors of A.
Answer:
The prime number is 61
Step-by-step explanation:
Hope this helps.
Good luck
Answer:
−11c4+5c2+3c−6 degree is 4
Step-by-step explanation:
9514 1404 393
Answer:
a) correct
b) needs parentheses: -1, (1±i√2)/3
Step-by-step explanation:
a) You can factor by grouping:
(x³ -2x²) -(5x -10) = x²(x -2) -5(x -2) = (x² -5)(x -2)
Roots are ±√5, 2.
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b) The sum of odd-degree coefficients is equal to the sum of even-degree coefficients (3-1 = 1+1), so one root is x=-1. Factoring out that leaves the quadratic factor ...
3x³ +x² -x +1 = (x +1)(3x² -2x +1)
The quadratic formula can be used on the quadratic factor to find its roots:
x = (-(-2) ±√((-2)²-4(3)(1)))/(2(3)) = (2 ±√-8)/6 = (1 ±√-2)/3
Roots are -1, (1 ±i√2)/3.
Answer:
b-2x=n
b-2x+2x=n+2x
b=n+2x
Step-by-step explanation:
add 2x to both sides of the equation and simplify