Answer:
The point is (2,-2)
Explanation:
|DF| = |DE| + |EF|
|DF| = 9x -36
|DE| = 47
|EF| = 3x+10
Substitute:
9x - 39 = 47 + 3x + 10
9x - 39 = 3x + 57 |+39
9x = 3x + 96 |-3x
6x = 96 |:6
x = 16
Put the value of x to the equation |EF| = 3x + 10
|EF| = (3)(16) + 10 = 48 + 10 = 58
Answer: |EF| = 58
Using a proportional relationship, the amounts are given as follows:
<h3>What is a proportional relationship?</h3>
A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:
y = kx
In which k is the constant of proportionality.
For this problem, we have that:
- The input variable is the number of tennis players.
- The output variable is the number of soccer players.
From the first row of the table, the constant is given as follows:
k = 35/15 = 7/3.
Hence the relationship is:
y = 7/3x.
For the second row of the table, we have that x = 3, hence:
y = 7/3 x 3 = 7.
For the third row of the table, we have that y = 84, hence:
84 = 7/3x
x = 84 x 3/7
x = 36.
Then the amounts are given as follows:
More can be learned about proportional relationships at brainly.com/question/10424180
#SPJ1
Answer:
4.969696 hours
Step-by-step explanation:
The distance traveled is shown through the following equations
Distance = velocity * time
This means that
4100=velocity*4
This means that ariplane 1 travles at 1025 km/hr
We can then subtract 200 from this to find that airplane two travels at a speed of 825 km/hr
Now we need to find how long it takes for that plane to travel 4100
So using the same equation
4100=825*time
Divison will tell us that the answer is around 4.9696 hours which is pretty much 5
Answer:
One adult ticket is $4 and one child ticket is $7
Step-by-step explanation:
Make a system of equations
2x + 10y = 78
8x + 5y = 67
Solve by elimination, multiply the 2nd equation by -2
2x +10y = 78
-16x -10y = -134
Add the equations
-14x = -56
x = 4
The price of one adult ticket is $4
Plug 4 in as x to find y
2(4) + 10y = 78
8 + 10y = 78
10y = 70
y = 7
The price of one child ticket is $7