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Lubov Fominskaja [6]
3 years ago
9

What’s the distance from c to d ?

Mathematics
1 answer:
Anon25 [30]3 years ago
3 0
It’s 5 since you’d use Pythagorean theorem
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Question: "If y > 3, what is the value of n ?"
iris [78.8K]

Answer:

y-3

Problem:

What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?

Step-by-step explanation:

Dividend=quotient×divisor+remainder

So we have

xy-3=(x-1)×(y)+remainder

xy-3=(xy-y)+remainder *distributive property

Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.

We need to get rid of minus y so we need plus y in the remainder.

We also need minus 3 in the remainder.

So the remainder is y-3.

Let's try it out:

xy-3=(xy-y)+remainder

xy-3=(xy-y)+(y-3)

xy-3=xy-3 is what we wanted so we are done here.

7 0
2 years ago
How to find the volume of L blocks?
choli [55]
 <span>Volume = L * W * H cubic units 

Surface Area = 2 * (LW + LH + WH) square units</span>
5 0
3 years ago
The price of an item has been reduced by 5%. The original price was $20. what is the price of the item now?
Makovka662 [10]

Answer:

I think its 19

7 0
3 years ago
The function h(x) is given below:
g100num [7]

Step-by-step explanation:

The domain and range of a function and its inverse are inverted i.e. The domain of the function will become range of its inverse and the range of the function will become the domain of its inverse.

When representing the function in ordered pairs, the first values in the pair represents the domain and second values represent the range of the function.

h(x) = {3,5),(5,-7)(6,-9)(10,-12)(12,16)}

Domain of h(x) is: {3, 5, 6, 10, 12}

Range of h(x) is: (5, -7, -9, -12, 16}

So,

Domain of h^{-1}(x) = Range of h(x) = (5, -7, -9, -12, 16}

Range of h^{-1}(x) = Domain of h(x) = {3, 5, 6, 10, 12}

Therefore, h^{-1}(x) will be represented as:

{(5,3), (-7,5), (-9, 6), (-12, 10), (16,12)}

It seems like you have made some error while writing the original function because of which we are not getting an exact match in the answer. However by looking at the answers, option B is the nearest most and seems the correct answer.

6 0
3 years ago
Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.
kap26 [50]

Answer: 68.1

Step-by-step explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

Area=\pi r^2/2

Area=\pi (3)^2/2=9\pi /2

The area of a rectangle is the length multiplied by the width:

Area=l*w

Area=6*9=54

The net area is the sum of the rectangle and the semi-circle:

Area=(9\pi /2)+(54)=68.1

8 0
2 years ago
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