Here's an example...
So, in our last example...
In the point ( -2, -1 ), x1 = -2 and y1 = -1 ... and, in the point ( 4, 3 ), x2 = 3 and y2 = 3
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 3 - ( -1 ) ) / ( 4 - ( -2 ) ) = 4 / 6 = 2 / 3
But, notice something cool...
The order of the points doesn't matter! Let's switch them and see what we get:
In the point ( 4, 3 ), x1 = 4 and y1 = 3 ... and, in the point ( -2, -1 ), x2 = -2 and y2 = -1
m = ( y2 - y1 ) / ( x2 - x1 ) = ( -1 - 3 ) / ( -2 - 4 ) = -4 / -6 = 2 / 3 ... Same thing!
Let's try our new formula with the second example in the last lesson:
It was a line passing through
( -1, 4 ) and ( 2, -2 )
m = ( y2 - y1 ) / ( x2 - x1 ) = ( -2 - 4 ) / ( 2 - ( -1 ) ) = -6 / 3 = -2
Answer:
Step-by-step explanation:
y = e^(-3x)
Stretch by factor of 4
y = 4e^(-3x)
Reflect across y axis
y = 4e^(3x)
Shift up by 5
y = 4e^(3x) + 5
Answer:
Step-by-step explanation:
U just set that as an equation. So it would be like this... 3x+3= 63.
3x + 3 = 63
-3 - 3
3x = 60
/3 /3
X = 20
Ughhh...the limit formula...this should be thrown in the trash the minute you start doing derivatives :P
(-8-9(t+d)-(-8-9t))/(t+d-t)
(-8-9t-9d+8+9t)/d
-9d/d (which is -9 for any value of d as well as when d approaches zero)
-9
So the instantaneous velocity is regardless of t or delta t
Answer:14
Step-by-step explanation:
44/3.14(pie)=14.01
