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3 years ago

What is the median of 36, 14, 21, 56, and 10?

Mathematics

2 answers:

Alexandra [31]3 years ago

6 0

The median is the middle number which is 21

dexar [7]3 years ago

4 0

The median is going to be the middle number in a sequence when the sequence is written from smallest value to latest value:

10, 14, 21, 36, 56

So, as the above person said, the median is 21 but it is still important to remember the aforementioned rule above.

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3 years ago

If AB is parallel to CD and the slope of CD is -5, what sis the slope of AB?

Lady bird [3.3K]

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The answer is D. -5

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3 years ago

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ki77a [65]

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3 years ago

Let V be the vector space P3[x] of polynomials in x with degree less than 3 and W be the subspace

Pepsi [2]

By definition, the span of two vectors is the set of all possible linear combinations of said vectors. So, any element in W is obtaining by choosing two numbers a,b and building

$a(7-8x-8x^2)+b(x^2-(5+6x)) = -8ax^2-8ax+7a+bx^2-6bx-5b$

(a)

So, you can show a nonzero polynomial in W by choosing any values of a and b, as long as they're not both zero. To keep it as simple as possible, we can choose for example a=1, b=0 and we obtain one of the base vectors of W:

$7-8x-8x^2$

(b)

Factoring the powers of x, we see that a generic polynomial in W looks like

$(b-8a)x^2-(8a+6b)x+7a-5b$

So, we must build a polynomial

$dx^2+ex+f$

such that it is not possible that

$\begin{cases}d=b-8a\\e=8a+6b\\f=7a-5b\end{cases}$

For example, let's try the polynomial $x^2+x+1$

We should solve the system

$\begin{cases}b-8a=1\\8a+6b=1\\7a-5b=1\end{cases}$

And you can check that it has no solutions. So, the polynomial $x^2+x+1$ does not belong to W. On the other hand, it surely belongs to V, because it is a polynomial with degree less than 3. So, the polynomial $x^2+x+1$ belongs to V/W.

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4 years ago

What is<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20-%2011%20%5C%5C%20" id="TexFormula1" ti

Ludmilka [50]

-22/3

................................

..

4 0

4 years ago