Ask question

Ask question

All categories

2 years ago

11

What does not belong |6|,6,-6,|-6|

2 answers:

Readme [11.4K]2 years ago

6 0

I am not very sure ask someone se

frutty [35]2 years ago

4 0

-6 does not belong because all the other number are positive and that one is negative

You might be interested in

A banana peel weighs 1/12 of the total weight of a banana. If an unpeeled banana balances a peeled banana of the same weight, p

Ilia_Sergeevich [38]

Answer:

11 ounces

Step-by-step explanation:

Unpeeled = X

Peeled = (1 - 1/12)X = (11/12)X

X = (11/12)X + (11/12)

X - (11/12)X = 11/12

(1/12)X = 11/12

X = 11 ounces

4 0

2 years ago

Read 2 more answers

Select the choice that has the correct area and perimeter for the figure .

laila [671]

Answer: B

Step-by-step explanation:

8 0

2 years ago

What is the GCF of 2+18+40

vlabodo [156]

2 is the GCF of <span>2+18+40
.</span>

6 0

2 years ago

Read 2 more answers

I need the answer, i'll give 2 points, lol

Dimas [21]

I think is 192 but I'm not sure

8 0

2 years ago

Read 2 more answers

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

2 years ago