All categories

3 years ago

What does not belong |6|,6,-6,|-6|

Mathematics

2 answers:

Readme [11.4K]3 years ago

6 0

I am not very sure ask someone se

frutty [35]3 years ago

4 0

-6 does not belong because all the other number are positive and that one is negative

You might be interested in

Please help me out

shutvik [7]

Answer:

18: 3/4

19: 5/8

20: 1/2

21: 9/10

22: 2/3

23: 5/6

24: 4/9

25: 2/7

26: 3/4

27: 7/10

28: 4/5 (I'm in a rush, so make sure to double check the answers)

4 0

3 years ago

The formula for the circumference of a circle is C=2nr, r is the radius and c is the circumference. The equation solved for r=c/

Fynjy0 [20]

Answer:

r = 8

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

16 pi = 2 * pi r

Divide each side by 2 pi

16 pi /2 pi = 2 pi r / 2 pi

8 = r

8 0

3 years ago

Read 2 more answers

What is the value of x in the solution to the system of linear equations? {y=3x+2 y=x-4 a –7 b –3 c 1 d 5

lyudmila [28]

Since y must equal both 3x+2 and x-4, we deduce that 3x+2 and x-4 must equal each other. So, we have

$3x+2=x-4 \iff 2x+2=-4 \iff 2x=-6 \iff x=-3$

5 0

3 years ago

Read 2 more answers

What values of x make this inequality true?

Alborosie

Answer:

A. x > 13

Step-by-step explanation:

x-3>10

x>10+3

x>13

3 0

3 years ago

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago