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xeze [42]
2 years ago
9

how do i do this ? i don’t know if i find the x value then that’s the answer or if i plug the x answer to both of those question

s

Mathematics
1 answer:
Nady [450]2 years ago
3 0

Answer:

x=12

Step-by-step explanation:

X=12 because we can see from the picture that the left line is drawn between parallel lines, meaning that the two angles (10x-13 and 4x+25) are supplementary, meaning that they add up to 180.

so we can now write an equation and solve it

(10x-13)+(4x+25)=180

14x+12=180

14x=168

x=12

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One angle measures 27° more than 2 times another. If the two angles are complementary, find the measures of the angles.
zepelin [54]

Answer:

<em>A. 21°, 69°</em>

Step-by-step explanation:

If you work by process of elimination all you have to do is take 27 away from the bigger degree of the two and see if it is 2x as much as the smaller degree.

Ex.

1. 69°-27°= 42°, which is 2x as many as 21°.

8 0
3 years ago
Can someone please help me
Slav-nsk [51]

Answer:

B

Step-by-step explanation:

The  sum of the angles of the triangle add up to 180 degrees.

x and y are equal to each other in this type of the triangle.

4 0
2 years ago
What is the solution to 2x + 8 &gt; 10 ?
denis-greek [22]
<span>2x + 8 > 10
Subtract 8 from both sides
2x>2
Divide 2 on both sides
Final Answer: x>1</span>
5 0
3 years ago
Read 2 more answers
ALGEBRA 1:
Phantasy [73]
64-16x+x^2 i had this same question and that’s the answer i put and for it right :)
3 0
3 years ago
Read 2 more answers
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

5 0
2 years ago
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