Answer:
a correlation near 0
Step-by-step explanation:
Answer:
Option 3: 
Graph C
Step-by-step explanation:
Find the solution of 

(multiplication property of equality)
Divide both sides by -1. Since we are dividing by a negative number, the sign would change

This means that the possible values of x are 8 and any number above 8.
Graphing this, the arrow of directed line would start at 8 and move towards our right hand.
Thus, the graph would be graph C in option C.
Answer: Choice A
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Explanation:
One shaded region is below the parabola, and the other shaded region is below the line. They both overlap outside the parabola, but under the straight line.
Since both shaded regions are below their respective boundaries, this means that we'll be using "less than" signs for each inequality. The solid boundary lines indicate "or equal to" is part of that as well.
Because of this, the answer is between A and D since both involve inequality signs that have "less than or equal to".
However, we can rule out choice D since the inequality
would have the boundary line
, and this boundary line has a positive slope. But notice how the red diagonal line slopes downward as we read from left to right. Therefore, the red line must have a negative slope. Luckily, choice A has one of the boundary lines as y = -x+3 to fit the description. So that's why choice A is the answer.
well, let's first off, expand the expression, 3x(x-4) => 3x²-12x, which we can also write as
f(x) = 3x² - 12x + 0
now, this is a quadratic equation with a leading term with a positive coefficient, namely its graph is a parabola, or a Cup-Shaped figure, so the graph comes from the top, goes down down down, reaches a U-turn, then goes back up up up.
the U-turn, or vertex of the quadratic, is the lowest point in the "cup".

Answer:
Step-by-step explanation:
Step 1: 6(x^2-1) [(6x-1)/(6(x+1)]
Step 2: [6(X+1) (X-1) (6X-1)] / 6(X+1)
Explanation: Factor out the (x^2-1)
Step 3: (6X-1) (X-1)
Explanation: Cancel out common terms on the top and the bottom of the fraction.
Step 4: 6X^2 - 6X-X+1
Explanation: Multiply out and Simplify
Answer: 6X^2 - 7x+1