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Gnom [1K]
3 years ago
9

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the

given equation. (2,-2);y=-x-2 A.y=-2x B.y=2x C.y=1/2x D.y=-x 2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6 A.y=-3/2x+1 B.y=-3/2x-1 C.y=-3/2x+2 D.y=-3/2x+4 3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3 A.y=2 B.y=2x+4 C.y=4x D.y=4 4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1 A.y=1/2x+1 B.y=-2x-1 C.y=1/2x-1 D.y=-1/2x-1 5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3) A.y=-1/2x+5 B.y=2x-5 C.y=1/2x-2 D.y=-1/2x+5/2
Mathematics
1 answer:
Alja [10]3 years ago
8 0
I dont know all of them sorry. But i think
Its d. If its a list of questions lol. But I could be wrong but i did the math 2 times.
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Find the next three terms in the sequence. 3, 9, 27, 81
Aliun [14]

Answer:

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4 0
3 years ago
Read 2 more answers
Write an equation in point slope form for the line that passes through (-5,6) and (-3,-9).
Finger [1]

\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad&#10;(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})&#10;\\\\\\&#10;slope = m\implies&#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-9-6}{-3-(-5)}\implies \cfrac{-9-6}{-3+5}\implies -\cfrac{15}{2}


\bf \begin{array}{|c|ll}&#10;\cline{1-1}&#10;\textit{point-slope form}\\&#10;\cline{1-1}&#10;\\&#10;y-y_1=m(x-x_1)&#10;\\\\&#10;\cline{1-1}&#10;\end{array}\implies y-6=-\cfrac{15}{2}[x-(-5)]\implies y-6=-\cfrac{15}{2}(x+5)&#10;\\\\\\&#10;y-6=-\cfrac{15}{2}x-\cfrac{75}{2}\implies y=-\cfrac{15}{2}x-\cfrac{75}{2}-6\implies y=-\cfrac{15}{2}x-\cfrac{87}{2}

8 0
3 years ago
-4/3x-6=-26 <br><br>A. -27<br>B. -15<br>C. 15<br>D. 27
JulsSmile [24]

Answer:

C. 15

Step-by-step explanation:

-4/3x-6=-26


The first step is to add 6 to each side

-4/3x-6+6=-26+6

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Now multiply by -3/4 to isolate x.

-3/4 * -4/3x = -3/4 * -20

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x = 15

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3 years ago
Rewrite the following equation in exponential form.<br> log 49(7) = 1/2
asambeis [7]
It would be log7squared(7)
4 0
3 years ago
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