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Gnom [1K]
4 years ago
9

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the

given equation. (2,-2);y=-x-2 A.y=-2x B.y=2x C.y=1/2x D.y=-x 2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6 A.y=-3/2x+1 B.y=-3/2x-1 C.y=-3/2x+2 D.y=-3/2x+4 3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3 A.y=2 B.y=2x+4 C.y=4x D.y=4 4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1 A.y=1/2x+1 B.y=-2x-1 C.y=1/2x-1 D.y=-1/2x-1 5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3) A.y=-1/2x+5 B.y=2x-5 C.y=1/2x-2 D.y=-1/2x+5/2
Mathematics
1 answer:
Alja [10]4 years ago
8 0
I dont know all of them sorry. But i think
Its d. If its a list of questions lol. But I could be wrong but i did the math 2 times.
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Help me please!! I don’t know what a quadratic graph is and need help answering this question! ASAP
sergeinik [125]

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C

Step-by-step explanation:

4 0
3 years ago
Based on the scatter plot, is there any positive, negative or no correlation? Explain
mixer [17]

Answer:

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-hope that helps! =)

6 0
3 years ago
Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions: y <
shepuryov [24]

Answer:

See explanation

Step-by-step explanation:

You have to graph the system of inequalities presented as

\left\{\begin{array}{l}y

Part A:

1. Draw a dotted line y=4x-2 (dotted because the sign < is without notion "or equal to"). Select one of two regions by substituting the coordinates of origin into inequality:

0

Since this inequlity is false, the origin doesn't belong to the shaded region, so you have to shade that part which doesn't contain origin (red part in attached diagram).

2. Draw a solid line y=-\frac{5}{2}x-2 (solid because the sign ≥ is with notion "or equal to"). Select one of two regions by substituting the coordinates of origin into inequality:

0\ge -\frac{5}{2}\cdot 0-2\\ \\0\ge -2

Since this inequlity is true, the origin belongs to the shaded region, so you have to shade that part which contains origin (blue part in attached diagram).

The intersection of these two regions is the solution area.

Part B:

Plot point (-2,-2). Since this point doesn't belong to the solution area, this is not a solution of the system of two inequalities. You can check it mathematically - substitute x=-2 and y=-2 into the system:

\left\{\begin{array}{l}-2

Both inequalities are false, so (-2,-2) doesn't belong to the solution area.

3 0
3 years ago
Now evaluate. Substitute −2 for x in the composition f(g(x)) = 4x6 + 4x3 + 1, then simplify. f(g(−2)) =
Viktor [21]
F(g(-2))=4(-2)^6+4(-2)^3+1
f(g(-2))=4(64)+4(-8)+1
f(g(-2))=256-32+1
f(g(-2))=224+1
f(g(-2))=225
4 0
4 years ago
Read 2 more answers
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