Consider the number 226981 since...
the units digit of 226981 is 1,
the units digit of its cube root is
also 1.
Now, the number obtained by striking out units, tens and hundred digits = 226.
=> 3. 3
<h2> 6. <226 <7 </h2>
tens digit of the cube root of 226981 is
<h2> 6</h2>
hence, 3._________
\/ 226981. =6
for more information
<h2>link/84016...</h2>
Answer:

Step-by-step explanation:
- given ap series : 8,3,-2,-7,-12....up to n terms
[the second term should be +3 or else it wont form AP series]
first term in the series: 8
common difference : 3-8 = -5
total terms : n
- the formula for sum of n terms in an ap =
![\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
a: first term
d: common difference
n : total terms
- by substituting value in the above formula,
- sum of the A.P:
![\frac{n}{2} [2(8)+(n-1)-5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2%288%29%2B%28n-1%29-5%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+-5n+5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B-5n%2B5%5D)
![\frac{n}{2} [21+-5n]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B21%2B-5n%5D)
=
Answer:
3.6
Step-by-step explanation:
It is a square based pyramid where,
Length (l)=9
Height (h)=10
Slant height (s)=11
For, volume (V) = 1/3 l^2*h
=1/3 9^2*10
=1/3 *810
=270
For, surface area = 2sl
= 2*11*9
=198
Y = x + 12
-x + y = -8
-x + y = -8
-x + x + 12 = -8
12 ≠ -8
The lines are parallel.