Answer:
the equation of the perpendicular bisector of segment AB is y = -2x + 7
Step-by-step explanation:
Going from B(-1, 4) to A(3, 6), x increases by 4 and y increases by 2. Thus, the slope of this line is m = rise / run = 2/4, or 1/2.
Any line perpendicular to the one joining A and B has a slope which is the negative reciprocal of 1/2: that'd be -2.
3 - 1 6 + 4
The midpoint of line segment AB is ( --------- , ---------- ), or (1, 5)
2 2
Thus, the perpendicular bisector passes through the midpoint (1, 5) and has slope -2:
Starting from y = mx + b, we get 5 = -2(1) + b, or 7 = b, and so the equation of the perpendicular bisector of segment AB is
y = -2x + 7
Answer:
Step-by-step explanation:
in tri ADC and tri BDC
∠ADC =∠BDC = 90
DC is common
AD = BD (given)
triangle ADC ≅ tri BDC by SAS congruency
hence AC = BC by CPCT ( congruent parts of congruent triangles)
hence, BC = 13
use quizzes and type line plot and your question it helps alot
Answer:
g=4
Step-by-step explanation:
If you're solving for g, you need to get it alone on one side. The way I did so was to subtract 7 from each side.
15 = 2g + 7
-7 -7
If you do that, the 7 on the right cancels out and you're left with 8 = 2g. To get the g alone, you divide it by it's base on both sides which in this case is 2.
8/2 = 2g/2
That will cancel the 2 out and will leave you with g on the right side and on the left side would be 4 because simple division (8/2=4)
Your final answer should be g = 4
Answer:
a and c i think.
Step-by-step explanation: