OK. Then let's solve for ' r '. That means you have to come up with an equation that says r = everything else.
Step #1:
Write the equation you're given: <span>S = L (1 - r)
Let's divide each side by ' L ': S/L = 1 - r
Subtract 1 from each side : S/L - 1 = -r
Multiply each side by -1 : <em> 1 - S/L = r</em>
and there you have it.
</span>
![\bf 8~~,~~\stackrel{8-2}{6}~~,~~\stackrel{6-2}{4}~~,~~\stackrel{4-2}{2}~~,~~\stackrel{2-2}{0}](https://tex.z-dn.net/?f=%5Cbf%208~~%2C~~%5Cstackrel%7B8-2%7D%7B6%7D~~%2C~~%5Cstackrel%7B6-2%7D%7B4%7D~~%2C~~%5Cstackrel%7B4-2%7D%7B2%7D~~%2C~~%5Cstackrel%7B2-2%7D%7B0%7D)
so, as you can see, the common difference is then -2, and the first term is clearly 8, thus
![\bf n^{th}\textit{ term of an arithmetic sequence}\\\\a_n=a_1+(n-1)d\qquad\begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\d=\textit{common difference}\\[-0.5em]\hrulefill\\a_1=8\\d=-2\\n=14\end{cases}\\\\\\a_{14}=8+(14-1)(-2)\implies a_{14}=8-26\implies a_{14}=-18](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20an%20arithmetic%20sequence%7D%5C%5C%5C%5Ca_n%3Da_1%2B%28n-1%29d%5Cqquad%5Cbegin%7Bcases%7Dn%3Dn%5E%7Bth%7D%5C%20term%5C%5Ca_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5Cd%3D%5Ctextit%7Bcommon%20difference%7D%5C%5C%5B-0.5em%5D%5Chrulefill%5C%5Ca_1%3D8%5C%5Cd%3D-2%5C%5Cn%3D14%5Cend%7Bcases%7D%5C%5C%5C%5C%5C%5Ca_%7B14%7D%3D8%2B%2814-1%29%28-2%29%5Cimplies%20a_%7B14%7D%3D8-26%5Cimplies%20a_%7B14%7D%3D-18)
B) y = -1/3 + 17
A line is perpendicular to another when the slope of one is the negative reciprocal of another line
example: negative reciprocal of x is -1/x
224 students have a sweatshirt.
-x+2 > 1
-x+2+x > 1+x .... add x to both sides
2 > 1+x
x+1 < 2
x+1-1 < 2-1 ... subtract 1 from both sides
x < 1
After solving for x, we get x < 1
To graph this, plot an open circle at 1 on the number line and shade to the left of this value. The open circle indicates that 1 is not part of the solution set.
If your teacher requires you to graph this on an xy grid, then draw a vertical line through 1 on the x axis. Make this vertical line a dashed line. Then shade the entire region to the left of this dashed line. Any point in this shaded region will have an x coordinate that is less than 1. The dashed line acts like the open circle. The dashed line tells the reader "any point on this dashed line is not part of the solution set"