Answer:
Step-by-step explanation:
ABC have sides: 5, 7 and 10
5^2 + 7^2 = 25+47 = 72 < 10^2
so triangle ABC is obtuse
JKL has sides: 12, 35 and 37
12^2 + 35^2 = 144 + 1225 = 1369 = 37^2
so triangle JKL is right-angled
PQR has sides 12, 10 and 16
12^2 + 10^2 = 144 + 100 = 244 > 16^2
so triangle PQR is acute
Answer:
5 5/6
Step-by-step explanation:
Change them into improper fractions. Multiply the denominator by the whole number and then add the numerator. Put that number over the denominator.
2 X 3 = 6 3 X 2 = 6
6 + 1 = 7 6 + 1 = 7
7/3 7/2
New expression: 7/3 + 7/2
Find a common denominator. Both denominators can go into 6.
14/6 + 21/6 = 35/6
Change this back into a mixed number by dividing.
Answer: 5 5/6
Since 6 is greater than 5 you input it into the last equation!
2•(6^2) -7
2•(36) -7
72 -7
65
The answer is 65!
Answer:
relating to or expressed as a number or numbers.
Step-by-step explanation:
Answer:
Step-by-step explanation:
No it isn't, because:
![{1.08}^{ \frac{1}{5} } = { \frac{108}{100} }^{ \frac{1}{5} } = { \frac{27}{25} }^{ \frac{1}{5} } = \sqrt[5]{ \frac{27}{25} } = 1.01551](https://tex.z-dn.net/?f=%20%7B1.08%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%7B%20%5Cfrac%7B108%7D%7B100%7D%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%7B%20%5Cfrac%7B27%7D%7B25%7D%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%5Cfrac%7B27%7D%7B25%7D%20%7D%20%20%3D%201.01551)
