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melisa1 [442]
3 years ago
9

S=L (1 - r), for r

Mathematics
1 answer:
maria [59]3 years ago
3 0
OK. Then let's solve for ' r '.  That means you have to come up with an equation that says     r =    everything else.

Step #1: 
Write the equation you're given:   <span>S = L (1 - r)

Let's divide each side by ' L ':      S/L = 1 - r

Subtract 1 from each side :         S/L - 1 = -r

Multiply each side by -1 :          <em>  1 - S/L = r</em>

and there you have it.
</span>
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Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. How many different groups
irakobra [83]

Answer:

56 groups of 5 Fabergé eggs can be taken.

Step-by-step explanation:

It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:

8C_{5}=\frac{8!}{5!(8-5)!}

8C_{5}=\frac{8!}{5!3!}

8C_{5}=\frac{8{\times}7{\times}6{\times}5!}{5!{\times}3{\times}2}

8C_{5}=56

Thus, 56 groups of 5 Fabergé eggs can be taken.

8 0
3 years ago
A calculator screen displays 9.837E8. Write this number in standard form.​
natta225 [31]

Answer:

983,700,000

Step-by-step explanation:

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6 0
3 years ago
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3+(-2) is_units from 3, in ___ the<br> direction.
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2, left direction (or negative if that’s an option)
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2 years ago
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The decay of 192 mg of an isotope is given by A(t)= 192e-0.015t, where t is time in years. Find the amount left after 55 years.R
finlep [7]
This is a typical radioactive decay problem which uses the general form:

A = A0e^(-kt)

So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

A = 192e^(-0.015*55)
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6 0
3 years ago
David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the
tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

  • A(t) is the amount of money after t years.  
  • P is the principal(the initial sum of money).  
  • r is the interest rate(as a decimal value).  
  • n is the number of times that interest is compounded per year.  
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • The APR is of 2.25%, hence r = 0.0225.
  • No information about the number of compounding per year, hence n = 1.

Item a:

P = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}

A(8) = 2389.66

Item b:

A(t) = 4000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}

(1.0225)^t = 2

\log{(1.0225)^t} = \log{2}

t\log{1.0225} = \log{2}

t = \frac{\log{2}}{\log{1.0225}}

t = 31.15

Item c:

A(3) = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}

P = \frac{2000}{(1.0225)^3}

P = 1870.85

A similar problem is given at brainly.com/question/24850750

7 0
2 years ago
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