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Pavlova-9 [17]
3 years ago
5

The student setup 30 games booths;the teachers also setup some. If 5/6 of the game booths were set up by the students, how many

game booths are there in total?
Mathematics
1 answer:
Ket [755]3 years ago
6 0
25 were set up by the students
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On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she ha
Sveta_85 [38]

Answer:

a. P(X=50)= 0.36

b. P(X≤75) =  0.9

c. P(X>50)=  0.48

d. P(X<100) = 0.9

Step-by-step explanation:

The given data is

x                      25        50       75        100          Total

P(x)                0.16       0.36    0.38    0.10          1.00

Where X is the variable and P(X) = probabililty of that variable.

From the above

a. P(X=50)= 0.36

We add the probabilities of the variable below and equal to 75

b. P(X≤75) = 0.16+ 0.36+ 0.38= 0.9

We find the probability of the variable greater than 50 and add it.

c. P(X>50)= 0.38+0.10=  0.48

It can be calculated in two ways. One is to subtract the probability of 100 from total probability of 1. And the other is to add the probabilities of all the variables less than 100 . Both would give the same answer.

d. P(X<100)= 1- P(X=100)= 1-0.1= 0.9

8 0
3 years ago
I need help do y’all know answer…..
Tems11 [23]

Answer:

x = 70

Step-by-step explanation:

14 + x = 84

x= 84 - 14

x = 70

here x is the games lost.

hope tgis helps !

4 0
2 years ago
Pete saves 4/5 of his wages each week.If he earns 150$ per week. How much did he save ?
yulyashka [42]

solution:

4/5 of $150

4/5 x 150

=120

so Pete saves $120 per week

5 0
3 years ago
laura has a mass of 60kg and is sitiing 265cm from the fulcrum of a seesaw. bill has a mass of 50kg. how far from the fulcrum mu
pickupchik [31]

Answer:

318 cm.

Step-by-step explanation:

Let x represent the distance between Bill and fulcrum.

We have been given that Laura has a mass of 60 kg and is sitting 265 cm from the fulcrum of a seesaw. Bill has a mass of 50 kg.

To balance the seesaw, the product of Laura's weight and her distance from fulcrum of seesaw should be equal to the product of Bill's weight and his distance from fulcrum of seesaw as:

50\text{ kg}\cdot x=60\text{ kg}\cdot 265\text{ cm}

\frac{50\text{ kg}\cdot x}{50\text{ kg}}=\frac{60\text{ kg}\cdot 265\text{ cm}}{50\text{ kg}}

x=\frac{6\cdot 265\text{ cm}}{5}

x=\frac{6\cdot 53\text{ cm}}{1}

x=318\text{ cm}

Therefore, Billy should be 318 cm far from the fulcrum to balance the seesaw.

4 0
3 years ago
I need help ASAP please, I have this due by tomorrow
3241004551 [841]

Answer:

30

Step-by-step explanation:

think im not to srue sorry

3 0
3 years ago
Read 2 more answers
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