What is the equation of the line that is perpendicular to the line 5x - 3y = 2 and passes through the point (-1.3)?
1 answer:
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The given function is,
The graph can be drawn as,
The period will be distance between two consequetive maximas,
Thus, period is correct.
The amplitude can be determined as,
Thus, amplitue is incorrect.
The range is,
Thus, the range is correct.
The midline is,
Thus, the midline is correct.
Thus, option (b) is the solution.
Answer:
The equation of line is y = 3 x - 1 , i.e option A .
The rate of change = m = 3
Step-by-step explanation:
Given as :
The points are
(,
) = (- 2, -7)
(,
) = (1 , 2)
Let The slope = m
<u>Now, The slope is calculated in points form</u>
So, Slope =
I.e m =
or, m =
I.e m = 3
So, The slope of points = m = 3
I,e Rate of change = m = 3
<u>Now, the equation of line in slope - point form can be written as</u>
y - = m ( x -
)
where m is the slope of line
i.e y - (-7) = ( 3 ) × ( x - (-2) )
or, y + 7 = 3 × (x + 2)
∴ y + 7 = 3 x + 6
Or, y = 3 x + 6 - 7
Or, y = 3 x - 1
So, The equation of line is y = 3 x - 1
Hence, The equation of line is y = 3 x - 1 , i.e option A .
And The rate of change = m = 3 Answer