What is the equation of the line that is perpendicular to the line 5x - 3y = 2 and passes through the point (-1.3)?

According to the histogram of travel times to work from the US 2000 census (Page 6 of "Journey to Work: 2000"), roughly what per

erastovalidia [21]

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

$\%Percentage = \frac{450}{500}$

Divide 450 by 500

$\%Percentage = 0.9$

Express as percentage

$\%Percentage = 90\%$

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

brainly.com/question/2776232

7 0

2 years ago

What numbers go in the blanks to make the equation true?

nirvana33 [79]

UMMMMMMMMMMMMMMMMMMMMMMMMM

8 0

3 years ago

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The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is $y=\frac{1}{3}x$

7 0

3 years ago

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54 divided by 2,808 the answer an worked out

NemiM [27]

0.019 is the correct answer. I hope this is the answer you are looking for! :)

4 0

3 years ago

3(x−7)+20=12+2(x−3). Pls help quickly

scZoUnD [109]

Step-by-step explanation:

3x-21+20=12+2x-6

3x-1= 6+2x

3x-2x=6+1

x=7

3 0

3 years ago

What is the equation of the line that is perpendicular to the line 5x - 3y = 2 and passes through the point (-1.3)?​

What is the equation of the line that is perpendicular to the line 5x - 3y = 2 and passes through the point (-1.3)?