<span>1. </span><span>4x –y = 8, the point (-4, 3)
Let’s say y = 0
=> 4x – 8
=> 4x / 4 = 8 /4
=> x = 2
So the point is (2 , 0).
Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=> m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1</span>
Solution:
Given:
To get sin 240 degrees:
240 degrees falls in the third quadrant.
In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.
Using the trigonometric identity;
Hence,
To get cos 240 degrees:
240 degrees falls in the third quadrant.
In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.
Using the trigonometric identity;
Hence,
To get tan 240 degrees:
240 degrees falls in the third quadrant.
In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.
Using the trigonometric identity;
Hence,
To get cosec 240 degrees:
To get sec 240 degrees:
To get cot 240 degrees:
The x-intercept is (-4/3,0).
Hope that helps!
Your equation: 4x² - 100 = 0
Factor the left side: (2x + 10) · (2x - 10) = 0
This equation is true if either factor is zero.
-- One factor: 2x + 10 = 0
Divide each side by 2: x + 5 = 0
Subtract 5 from each side: x = -5 .
-- The other factor: 2x - 10 = 0
Divide each side by 2: x + 5 = 0
Add 5 to each side: x = 5 .