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jolli1 [7]
3 years ago
8

I need number 3 and 4 and I need all the possible work shown thank you!

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0
3. Since 8 years have passed(not including 1997) you would substitute 8 into the given equation. That would give you B(171)
4. I don't know:(
Hope that helped a little bit
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Write 4/27 as the product of a prime raised to a power​
Sphinxa [80]

Answer:

write 4/27 as the product of a prime raised to a power

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Find the unit rate and slope of the graph (ignore what I put down)
Vilka [71]

Answer:

slope: 5/7

0.714 mile per hour

Step-by-step explanation:

slope: find the point where the line is right on the line graph, put y/x which is 10/14 make the fraction smaller which is 10/14 = 5/7(I divide the denominator and nominator by 2)

Mile per hour: 5/7 cross multiply with x/1, make into an equation:

7x=5 x 1

7x = 5

x = 0.714

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Luis distributes 49 roses equally among 7 friends. Then, 3 of his friends combine the roses they received to make a bouquet. How
antoniya [11.8K]

Answer:

21 roses

Step-by-step explanation:

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Each friend got 7 roses.

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3 years ago
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Sphinxa [80]
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3 years ago
Read 2 more answers
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
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