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kaheart [24]
3 years ago
13

The cost of a babysitting on a cruise is 10 for the first hour, and 12 for each additional hour. If the total cost of baby Aaron

was 58, how many hours was Aaron at the sitter?
Mathematics
1 answer:
Sliva [168]3 years ago
4 0

<u>Answer:</u>

5 hours  was Aaron at the sitter

<u>Explanation: </u>

Cost of baby sitting for the first hour: 10

Cost of baby sitting for additional hour= 12

Total cost of babysitting= 58

Since the cost of first hour is 10

Hence  the remaining cost after first hour

= 54-10

=48

Which means 1 hour  is consumed in the first hour

Now to calculate the remaining hours for every additional hour

= \frac{48}{12}

=4 hours

Hence the total hour Aaron was with the sitter

= 1 hour + 4 hours

= 5 hours

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Answer:

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I need help &amp; a explanation on the answer please !
GrogVix [38]

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2 years ago
Read 2 more answers
A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.
Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be 4w+3l.

We can set our given information in an equation 4w+3l=300.

The area of the two pens would be A=2l\cdot w.

From perimeter equation, we will get:

w=\frac{300-3l}{4}

Substituting this value in area equation, we will get:

A=2l\cdot (\frac{300-3l}{4})

Since we need to maximize area, so we need to find derivative of area function as:

A=\frac{600l-6l^2}{4}

Bring out the constant:

A=\frac{1}{4}*\frac{d}{dl}(600l-6l^2)

A=\frac{1}{4}*(600-12l)

A=150-3l

Now, we will set our derivative equal to 0 as:

150-3l=0

150=3l

\frac{150}{3}=\frac{3l}{3}

50=l

Now, we will substitute l=50 in equation w=\frac{300-3l}{4} to solve for width as:

w=\frac{300-3(50)}{4}

w=\frac{300-150}{4}

w=\frac{150}{4}

w=37.5

Therefore, width of 37.5 feet and length of 50 feet will maximize the area.

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3 years ago
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The limit it converges to is 0

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3 years ago
PLEASE MATH HELP WILL GIVE BRAINLIEST!!
saw5 [17]
Hello,

Answer B

(x-(-5))²+(y-2)²=5²

(x+5)²+(y-2)²=25

5 0
3 years ago
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