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Minchanka [31]
3 years ago
5

What is the discrimination of 3x^2+6x=2

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0
60
D>0, there are 2 distinct real roots

Explanation:

3x2+6x−2=0
a=3,b=6,c=−2

The formula for discriminant is b2−4acSubstitute the given values.

b2−4ac
(6)2−4(3)(−2)
=60
therefore, D>0, there are 2 distinct real roots

zysi [14]3 years ago
4 0
Discriminant, not discrimination.  I'm not discriminating against you.  ;)

You must re-write   3x^2+6x=2    in standard form:     <span>3x^2 + 6x - 2 

Here a=3, b=6 and c= -2

The discriminant is b^2 - 4ac.  Here, it's     6^2 - 4(3)(-2), or 36 + 24, or 60.

This quadratic has two real, unequal, zeros.</span>
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Galina-37 [17]
Try writing it in point-slope form and you will see why you have a problem.

slope m is equal to (y2-y1)/(x2-x1):

m = (y2-y1)/(x2-x1) = (2-6)/(-6 - -6) = -4/0

The denominator has a zero, so it is undefined.

Since the point-slope form requires "m" to be defined, you can't write the equation of the line using point-slope form.


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4 years ago
Josh went to a restaurant for dinner. The cost of the
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3 years ago
What is the value of x in 2(5^x) = 14?
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