1. Understand what happens
2. Willingly take part
3. Experience discomfort
28: x+y = 90
we substitute y with the given function 4x - 10
x + 4x - 10 = 905x -10 = 90 5x = 100= 100 ÷ 5x = 20, now you can substitute x in 4x - 10 =4(20) - 1080 - 10 = 70, which makes sense as 20º +70º = 90ºyour 2 angles are 20º and 70º
29: x + y = 90 x = 2y
Same thing we did above, substitute the given variable into the given equation
so, 2y + y = 90 = 3y=90, divide the 3 to both sides, y = 30, now substitue the y into your given x variable.x = 2(30)x= 60this makes sense as 60º + 30º do equal 90ºyour two angles are 60º and 30º30: x + y = 90 y = 2 (x - 15)ill do this one without explanation as you know what I am doing from the above examples. here is the work:
x + 2(x-15)=90 (simplify)
x+2x-30 = 903x-30=903x = 120x = 40now input to other equation2(40 - 15) = y (USE PEMDAS)2(25) = yy = 50
makes sense because 50º + 40º = 90ºyour two angles are 50º and 40º
400000/x=100/10
<span>(400000/x)*x=(100/10)*x - </span>we multiply both sides of the equation by x
<span>400000=10*x - </span>we divide both sides of the equation by (10) to get x
<span>400000/10=x </span>
<span>40000=x </span>
<span>x=40000</span>
The coordinates of the point that is one-half the distance between A(-1,-2) and B(6,12) is (2.5,5)
What is the midpoint?
The mid-point lies midway between the two ends. Its x value lies in the middle of the other two x values. Its y value lies in the middle of the other two y values.
Given,
Let M is a midpoint of AB, then
The midpoint of point AB is M(2.5,5)
Therefore, the coordinates of the point which is one-half the distance between A(-1,-2) and B(6,12) is M(2.5,5).
To learn more about the midpoint
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Answer:
36 and 216
Step-by-step explanation:
Let x and y be LCM and GCF respectively.
We are told that the sum and the difference between the LCM and GCF of two numbers is 252 and 180.
Upon using our information we will get a system of equations.
We will use substitution to solve this system of equations.
Now let us find x using equation 1,
Therefore, LCM is 216 and GCF is 36.
Let a and b our numbers. Now let us find numbers using this information.
We are given that one of them is more than twice the other.
There can be several such numbers. 36 and 216 can also be numbers. Let us check these numbers.
LCM of 36 and 216 is 216 and GCF is 36 and it satisfies our condition that because 216 is more than twice 36.
Therefore, our numbers will be 36 and 216.