Answer:
After 4secs
Step-by-step explanation:
Given the function of the height expressed as;
h(t)=-16^2 + initial height
If initial height = 256, then;
h(t) = -16t^2 + 256t
The pebble will hot the ground at when h(t) = 0
Substitute
0 = -16t^2 + 256t
16t^2 = 256
t^2 = 256/16
t^2 = 16
t = 4
Hence the pebble will hit the ground after 4secs
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The weight of the bucket is 
The depth of the well is 
The weight of the water is 
The rate at which the bucket with water is pulled is 
The rate of the leak is 
Generally the workdone is mathematically represented as
]
Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

Here I is the rate of water loss in lb/ft mathematically represented as

=> 
=>
So

=> 
So
]
=> ![W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.](https://tex.z-dn.net/?f=W%20%3D%20%20%5B47x%20-%20%5Cfrac%7B0.1x%5E2%7D%7B2%7D%20%5D%7C%5Cleft%2060%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
=> ![W= [47(60) - 0.05(60)^2]](https://tex.z-dn.net/?f=W%3D%20%5B47%2860%29%20-%200.05%2860%29%5E2%5D)
=> 
The answer to your question is 40
For this case, the first thing we must do is define a variable.
We have then:
p: rate in miles per hour for the last 1.5 hours
We now write the equation that models the problem.
We have then:

Rewriting we have:

From here, we clear the value of p.
We have then:
Answer:
DeAngelo's rate for the last 1.5 hours of his run is 7 miles per hour.
Y=7/4x+9/7 is an equation perpendicular to that