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3 years ago

How do you solve two steps equations with integers for example: 5x + 3 = 8

Mathematics

2 answers:

aleksley [76]3 years ago

8 0

Subtract 3 from both sides
5x=5
Divide both sides by 5
x=1

Scrat [10]3 years ago

5 0

First subtract the # without a x (so 3) and the do it it to the # on the other side if the equal sign so now you should have 5x=5 and then just subtract the # infront if the x (So 5) and do that on the other side so then you should have x=1

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2 years ago

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ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

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$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

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