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2 years ago

A coca cola costs 150 yen. You buyed 30 bottles of cola and sold them at the price of 155 yen each. Find profit %

Mathematics

1 answer:

bazaltina [42]2 years ago

7 0

<h3><u>Question:</u><u>-</u></h3>

A coca cola costs 150 yen. You buyed 30 bottles of cola and sold them at the price of 155 yen each. Find profit %

<h3><u>Answer</u><u>:</u><u>-</u></h3>

3.33%

<h3><u>Explanation</u><u>:</u><u>-</u></h3>

Cost price = ¥150

Selling price = ¥155

Total profit = Selling price - Cost price

→ = ¥155 - ¥150

→ = ¥5

Profit % = Profit × 100/cost price

️ = 5 × 100/150

️ = 10/3 = 3.33%

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Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a $\frac{1}{4} = 0.25$ probability of getting ir right. So $\pi = 0.25$ . There are five questions, so $n = 5$ .

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

$P = 0.75(0.25) = 0.1875$

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: $P = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955$

$P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637$

$P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592$

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

$P = P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879$

$P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146$

$P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001$

$P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035$

There is a 10.35% probability that she gets the majority of the questions right.

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maks197457 [2]

The labor-force participation rate of Belgium in 2017 was 77.78%

Given:

Adult population = 4500

Number of employed in 2017 = <em>2800</em>

Number of Unemployed in 2017 = 700

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Adult Population in 2016 = 3500

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3 years ago

A coca cola costs 150 yen. You buyed 30 bottles of cola and sold them at the price of 155 yen each. Find profit %​

A coca cola costs 150 yen. You buyed 30 bottles of cola and sold them at the price of 155 yen each. Find profit %