AVERAGE between 90 and 100%
means not including 90 and 100% but not including 90 or 100%
average=(sum of values in set)/(how many values in the set)
so
4 exams, so there are 4 values
average=(sum)/4
the sum is the known+unknwon
sum=76+99+86+x
so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100
lets say average=a
a=sum/number
a=(76+99+86+x)/4
90<(76+99+86+x)/4<100
90<(76+99+86+x)/4 and (76+99+86+x)/4<100
solve each for x and find intersection
90<span><</span>(76+99+86+x)/4
times 4 both sides
360<span><</span>261+x
minus 261 both sides
99<span><</span>x
(76+99+86+x)/4<u><</u>100
times 4 both sides
261+x<u><</u>400
minus 261 both sides
x<u><</u>139
so
99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100
interval notaion is
[99,100]
answer is 2nd one
Answer:
151.5 cm^2
Step-by-step explanation:
lets cut stright acrros so you have a triangle 13 (base) by 3 cm (high)
area of a triangle is 1/2 base times hight --> 13x3/2 = 19.5cm^2
now lets doi the rectangle that is 12 by 11
Length times hight is the area is 132
add both areas 132 + 19.5
Answer:
Ehhh
Step-by-step explanation:
Answer:
D.16.5m
because circumference=21/7×5.25
=16.5m
<span>5^2 + 10^2 = 125
c^2 = 125
c = √125 = √(25•5) = = 5√5</span>
