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ivann1987 [24]
3 years ago
6

Drag the numbers to order them from least to greatest.

Mathematics
2 answers:
Licemer1 [7]3 years ago
5 0
Least to Greatest: -4 1/2, -1/2, 1/4, 2/3, 2 1/3



notsponge [240]3 years ago
4 0

Answer:

-4 1/2, -1/2, 1/4, 2/3, 2 1/3

Step-by-step explanation:

Given the numbers in the order below;

-1/2, 1/4,2/3,-4 1/2, 2 1/3

Firstly we will convert this fractions to percentage.

For -1/2;

-1/2×100 = -50%

For 1/4;

1/4×100 = 25%

For 2/3;

2/3×100 = 66.7%

For -4 1/2 = -9/2

-9/2×100 = -450%

For 2 1/3 = 7/3

7/3×100 = 233.1%

Ordering the numbers from least to greatest means arranging from lowest to highest(ascending order of magnitude)

During arrangement, the negative values are the least and that come first followed by the positive values. The arrangements gives;

-450%, -50%, 25%, 66.7%, 233.1%

According to their fractions will give us;

-4 1/2, -1/2, 1/4, 2/3, 2 1/3 (From lowest to greatest)

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Olenka [21]

Answer:

1 is not a transformation

2 is a reflection

3 is a dilation

4 is a translation

Step-by-step explanation:

8 0
3 years ago
Cameron is older than Hassan. Their ages are consecutive integers. Find Cameron's
Alexxandr [17]

Answer:

25

Step-by-step explanation:

So consecutive integers, just means they're separated by a value of 1. This can be generally expressed as "a, a+1" where these two values would be consecutive integers assuming "a" is an integer.

So let's express Hassan's age as the variable "x", since it's unknown. Since Cameron is older, and by definition of a consecutive integer, Cameron's can be expressed as "x+1"

So the equation we need to set up is Cameron's age + 5(Hassan's age) = 145

So we can substitute the variables we defined to express Cameron and Hassan's age: (x+1) + 5(x) = 145

Distribute the 5: x+1+5x

Add like terms: 6x+1 = 145

Subtract 1 from both sides: 6x=144

Divide both sides by 6: x=24

Since we used "x" to represent Hassan's age, Hassan's age is 24. Since we used "x+1" to represent Cameron's age, Cameron's age is "24+1" which is just 25

6 0
2 years ago
What’s the domain and range of this graph?
avanturin [10]

Given:

The graph of a downward parabola.

To find:

The domain and range of the graph.

Solution:

Domain is the set of x-values or input values and range is the set of y-values or output values.

The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.

Domain = R

Domain = (-∞,∞)

The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.

From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.

Range = All real numbers less than or equal to -4.

Range =  (-∞,-4]

Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].

3 0
3 years ago
Can someone help me with 10 math questions (:
olga2289 [7]
So volue of a cone=1/3 times (area of base[which is a circle]) times height

area of base=area of circle=pi time radius^2
area=pi times 5^2
area=pi times 25=25pi

1/3 times 25pi times 18
25pi times 18 times 1/3
25pi times 18/3
25pi times 6=150pi


the answer is 150π in^3 or 150π cubic inches or C

( to solve, aprox pi to 3.141592 an multiply 150 by 3.141592=471.239 in^3)
3 0
3 years ago
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

3 0
3 years ago
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