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Alex_Xolod [135]
3 years ago
9

Use compatible numbers to find two estimates that the quotient is between. 1,754 divided 9

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0

Answer: Between 194 and 195

Step-by-step explanation: Compatible numbers are numbers in pairs that by mental exercise one can easily add, subtract, multiply, or divide. This is applied usually in estimation to approximate a calculation. Here, you replace actual numbers with compatible numbers (easy to estimate pairs).

Two numbers with close quotients with 1754 on dividing by 9 are by estimation 194 and 195. To check, on multiplying these figures by 9 you get 1746 and 1755 respectively. 1755 is actually very close to the required result, therefore 195 is a better estimate than 194 if we were to pick just one. So 194 and 195 fits perfectly

andre [41]3 years ago
4 0
In between 194, and 195, but closer to 195
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State whether each sequence is arithmetic and justify your answer. If the sequence is arithmetic, write a recursive and an expli
nasty-shy [4]

Answer:

Part A

f(n)=52-12(n-1)

f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.

Part B

(2,4,8,16,32)\: \: Geometric Sequence

Part C

1/4,3/4,5/4,7/4,9/4

g(n)=\frac{1}{4}+\frac{2}{4}(n-1)\\f(n)=\left\{\begin{matrix}1/4if \: \:n=1 & \\ f(n+1)+2/4& if\: n\geq 2 \end{matrix}\right

Part D:

h(n)=1.1+0.4(n-1)\\h(n)=\left\{\begin{matrix}1.1 & if\:n=1 \\ h(n+1)+0.4 & if\:n\geq 2\end{matrix}\right

Step-by-step explanation:

By definition, an Arithmetic Sequence holds the same difference between each following number.

Part A

(52,40, 28, 16)\\52-40=12\\40-28=12\\28-16=12\\d=12

<u>Explicit Formula</u>

To write an explicit formula is to write it as function.

f(n)=52-12(n-1)

<u>Recursive Formula</u>

To write it as recursive formula, is to write it as recurrence given to some restrictions:

f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.

Part B

(2,4,8,16,32)\: \:

Geometric Sequence, since 2*2=4 8*2=16 and 16*2=32 and 8+2=10 8+16=24

Part C

(\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4},\frac{9}{4})\\\

Arithmetic Sequence, difference

d=\frac{2}{4}

<u>Explicit Formula:</u>

g(n)=\frac{1}{4}+\frac{2}{4}(n-1)

<u>Recursive Formula</u>

g(n)=\left\{\begin{matrix}\frac{1}{4} &if\:n=1 \\ g(n+1)+\frac{2}{4} &if\: n\geq 2\end{matrix}\right.

Part D

(1.1,1.5,1.9,2.3,2.7) Arithmetic Sequence, difference d=0.4

<u>Explicit formula</u>

h(n)=1.1+0.4(n-1)\\

<u>Recursive Formula</u>

h(n)=\left\{\begin{matrix}1.1 &if\:n=1 \\ h(n+1)+0.4 &if\: n\geq 2\end{matrix}\right.

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