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pychu [463]
3 years ago
14

Kyle mows 5 lawns a day 3 days a week 4 weeks a month and 6 months a year. He makes 20.09 per lawn. His expenses are: 8.00 a wee

k for lower operation, travel expenses is 24.00 a month and the tax on his NET income ( net= money after expenses are deducted) is 13.0%%, what is his income
Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0
If you want to know the work its a lot the  answer comes down to his income was $42.07 is his income
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2/3 / (-9/4)<br><br> 2/3 divided by (-9/4)
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The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 3.6 cars and a
Iteru [2.4K]

Answer:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Then we have:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

With the following parameters:

\mu_{\bar X}= 3.6

\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of cars running a red light of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

With the following parameters:

\mu_{\bar X}= 3.6

\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5

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3 years ago
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