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pychu [463]
3 years ago
14

Kyle mows 5 lawns a day 3 days a week 4 weeks a month and 6 months a year. He makes 20.09 per lawn. His expenses are: 8.00 a wee

k for lower operation, travel expenses is 24.00 a month and the tax on his NET income ( net= money after expenses are deducted) is 13.0%%, what is his income
Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0
If you want to know the work its a lot the  answer comes down to his income was $42.07 is his income
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Evaluate 2/3x + 1/2 for x=3/4 (I just copied the exact question)
Travka [436]

Answer:

1

Step-by-step explanation:

(⅔)(¾) + ½

½ + ½

= 1

6 0
3 years ago
Write an expression equivalent to 6x+3y-4x+2
ch4aika [34]

Answer:

10x+3y+2

Step-by-step explanation:

5 0
3 years ago
The graph below shows the height an elevator travels, y, in x seconds:
ad-work [718]

9514 1404 393

Answer:

  25 (ft/s)

Step-by-step explanation:

The "rate of change" is taken to mean the "rise" divided by the "run". Here, adjacent points differ in their y-value by 25 ft and their x-value by 1 second.

The rate of change is ...

  rise/run = (25 ft)/(1 second) = 25 ft/second

Usually, we're just interested in the numerical value: 25.

_____

<em>Additional comment</em>

The graph is mis-labeled. It is not showing "rate of ascent." It is showing height as a function of time. The "rate of ascent" is the <em>slope</em> of the line on the graph, not its <em>value</em>.

6 0
2 years ago
Given that triangle ABC is congruent to triangle DEF find x and y
Charra [1.4K]
X will equal 12, and y will equal 18.
6 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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