Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
the first answer choice, associative property of addition
hope this helps. gl!
The statement that -6 is in the domain of f(g(x)) is true
<h3>Complete question</h3>
If f(x) = -2x + 8 and g(x) =
, which statement is true?
- -6 is in the domain of f(g(x))
- -6 is not in the domain of f(g(x))
<h3>How to determine the true statement?</h3>
We have:
f(x) = -2x + 8

Start by calculating the function f(g(x)) using:
f(g(x)) = -2g(x) + 8
Substitute 

Set the radicand to at least 0

Subtract 9 from both sides

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........
Hence, the statement that -6 is in the domain of f(g(x)) is true
Read more about domain at:
brainly.com/question/24539784
#SPJ1
Using the distributive property, you can distribute the 7 to y and -4. In other words, multiply the number outside of the parenthesis by each of the numbers in the parentheis.
7*y+7*-4
=7y-28
:)