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pogonyaev
3 years ago
12

Help me with this please

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

The first one is a function because, for each x-value (domain value) there is exactly one y-value (range value).

The second one is not a function because, not each x-value (domain value) has exactly one y-value (range value). The domain value of 5 has two range values of 13 and 9.

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Read 2 more answers
Factorise <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="lat
Amanda [17]

Answer:

a1= 1   q= −sinx  , dla |q| <1   , ta suma jest zbieżna  

 a1   1  

S=  

=  

 1 −q   1+sinx  

w mianowniku podobnie:   a1=1  ,  q= sinx  , dla  | sinx| <1

 1  

S=  

 1 −sinx  

i mamy równanie:

 

1  

1+sinx  

 

 

= tg2x

 

1  

1− sinx  

 

Step-by-step explanation:

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