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pogonyaev
2 years ago
12

Help me with this please

Mathematics
1 answer:
Len [333]2 years ago
8 0

Answer:

The first one is a function because, for each x-value (domain value) there is exactly one y-value (range value).

The second one is not a function because, not each x-value (domain value) has exactly one y-value (range value). The domain value of 5 has two range values of 13 and 9.

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Find x to the nearest tenth
jeka57 [31]

Answer:

x=30.6

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Use the estimate in the text based on the Prime Number Theorem to give approximate values of the following. (a) The number of pr
ozzi

Answer:

a)148.47

b)148.34

Step-by-step explanation:

Let π(x) be the prime-counting function that gives the number of primes less than or equal to x, for any real number x. For example, π(7) = 4 because there are four prime numbers (2, 3, 5, 7) less than or equal to 7.

We can see that π(7)=π(10) because there are four prime numbers (2,3,5,7) less than or equal to 10.

A good aproximation for π(x) is x / log x, where log x is the natural logarithm of x.

a)The number of primes between 1 and 1030.

1030/log(1030)=148.47

b) The number of primes between 1 and 1029.

1029/log(1029)=148.34

 Extra: π(1029)=π(1030) because 1030 is not a prime.

5 0
3 years ago
HELP PLEASE ILL BE GIVING OUT 13 POINTS TO WHOEVER ANSWERS EARLY! PLEASE QUICKLY HELP
jok3333 [9.3K]

<em>Answer:</em>

D)(6(-3)/9)

<em>Step-by-step explanation:</em>

<em>                  -1</em>

<em>Simplify   ——</em>

<em>                  3 </em>

<em>       -1</em>

<em>6 • ——</em>

<em>       3 </em>

<em>-2</em>

<em>If this was helpful, please mark brainliest. Have a beautiful day!</em>

<em />

7 0
3 years ago
The rate at which a quantity of a radioactive substance decays is proportional to the quantity of the substance. The constant of
Butoxors [25]

Answer:

\frac{dN}{dt} = λN           N(0) = 6

N(t) = N₀e^(λt)

Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing  the information briefly and stating the  variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality  is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays (\frac{dN}{dt}) is proportional to the quantity of the substance (N)  and λ is the constant of proportionality  is called the decay constant or decay rate :

\frac{dN}{dt} = λN          

N(t) = N₀e^(λt) ......equ 1

substituting the value of  N₀ = 6 into equation 1

N(t) = 6e^(λt)

3 0
3 years ago
Please help me please please
sertanlavr [38]

Answer:

ASAAAA KA BLEEE

Step-by-step explanation:

<h3>wajahhahahahahahahahahahahahahahahabahahahahahaahahahahhahahahahahahahahahahahahaha</h3>
8 0
3 years ago
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