Construct the perpendicular bisector of ST
Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a) 
(cumulative)
(b) P(X = 8) = 0.0653 (density)
(c) 
(cumulative)
(d) 
(cumulative)
(e) 
The error bars are used to indicate the variability of the data presented in a graph.
There are several quantities that can be used to generate error bars in the graph. These are:
standard deviation
standard error
confidence interval
Usually, one standard deviation above and below the mean is used although it is advised to indicate which variability data is used to generate the error bars in the graph since the 3 quantity given are not equal.
Answer:
a) y =2/3 x + 7.
b) x = -1
c) y = -4/5 x - 1/5
d) y = -3/2 x + 5/2.
Step-by-step explanation:
a) Intercept form y = mx + b where m = 2/3 and b = 7
b) y can take any value but x is always -1.
c) Slope m = (-1-3)/ (1 - -4)
= -4/5
Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:
y - y1 = m(x - x1)
y - -1 = -4/5(x - 1)
y + 1 = -4/5x + 4/5
y = -4/5 x - 1/5
d) The slope m of the line perpendicular to this line is:
-1 / 2/3
m = -3/2.
When x = -1 , y = 4 so using the slope intercept form of a line
y = mx + b
4 = -3/2 * -1 + b where b = the y-intercept.
4 = 3/2 + b
b = 4 - 3/2 = 5/2.
The equation is y = -3/2 x + 5/2.
Answer:
$1,635
Step-by-step explanation:
she makes $45 a year so if you multiply that by 3 you get $135
