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4 years ago

What is the measure of the diameter? What is the measure of the circumference?

Mathematics

2 answers:

miss Akunina [59]4 years ago

6 0

Answer:

Radius of circle = 3cm

we need to find the circumference and diameter of circle.

Dimeter of circle = 2× Radius

Diameter of circle = 2 × 6

Diameter of circle = 6cm

Circumference of circle = 2πr

Circumference of circle = 2 × π × 6

Circumference of circle = 12π

Lesechka [4]4 years ago

5 0

Answer:

circle

radius

Step-by-step explanation:

1 ) The diameter measures the circle at its largest point across. Another definition that is related to the diameter is the radius. It is the measurement from the center of the circle to its edge.

2) When a circle's diameter is 1, its circumference is π. When a circle's radius is 1—called a unit circle—its circumference is 2π. -

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Answer:

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Step-by-step explanation:

-6x-42=-4x-2

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3 years ago

3. Given that a is 30% of b, find the value of a/4b

Karolina [17]

Answer:

a/4b = 0.075

Step-by-step explanation:

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3 years ago

If f(x) =-2+8 and g(x) = square root of x+9 which statement is true

lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = $\sqrt{x + 9$ , which statement is true?

-6 is in the domain of f(g(x))
-6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

$g(x) = \sqrt{x + 9$

Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute $g(x) = \sqrt{x + 9$

$f(g(x)) = -2\sqrt{x + 9} + 8$

Set the radicand to at least 0

$x + 9 \ge 0$

Subtract 9 from both sides

$x \ge -9$

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true