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2 years ago

Write 19.4 in expanded form

Mathematics

1 answer:

Natali5045456 [20]2 years ago

6 0

The answer is 10+9+0.4

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A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

kondor19780726 [428]

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

$^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15$

Hence , the number of different combinations of 2 vegetables are possible = 15 .

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3 years ago

PLZ HELP ME GEOMETRY<br> question is below

konstantin123 [22]

The missing justification is for the statement that three angles add to a particular angle. The appropriate choice is ...

... c. Angle Addition Postulate

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2 years ago

12-3 (2w+1)=7w-3 (7+w)

n200080 [17]

$12-3(2w+1)=7w-3(7+w) \\ \\ 12-6w-3=7w-21-3w \\ \\ 9-6w=4w-21 \\ \\ -6w-4w=-21-9 \\ \\ -10w=-30 \\ \\ \boxed{x=\frac{-30}{-10}=3}$

3 0

3 years ago

Read 2 more answers

Find two numbers whose sum is 44 and whose difference is 6.<br> smaller number<br> larger number

Anna [14]

X+ y = 44
x - y = 6
—————
2x = 50

x = 25
y = 44-x = 19

3 0

3 years ago

The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone

ad-work [718]

Answer:

Part 1) The exponential function is equal to $y=1,350(0.95)^{x}$

Part 2) The population in 2010 was $992\ fish$

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

$a=1,350\ fish$

$b=(100\%-5\%)=95\%=0.95$

substitute

$y=1,350(0.95)^{x}$ ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

$y=1,350(0.95)^{x}$

For $x=(2010-2004)=6\ years$

substitute

$y=1,350(0.95)^{6}=992\ fish$

7 0

3 years ago