Answer:
m<CAO = 56
Step-by-step explanation:
When two parallel lines are intersected by a transversal, the same-side interior angles are supplementary, meaning that their angle measures add up to (180) degrees. Using this information, substitute in the given values and solve for the unknown,
(m<DOA) + (m<CAO) = 180
Substitute,
3x + 40 + 2x = 180
Simplify,
5x + 40 = 180
Inverse operations,
5x + 40 = 180
-40 -40
5x = 140
/5 /5
x = 28
Now substitute the value of (x) back into the given expression for the value of (<CAO). Solve to find the numerical value.
<CAO = (2x)
= 2(28)
= 56
it would be y = -12/5. Hes the work. hope this helps!
Answer:
Make an eqaution from here.
Let’s make evening 2 “x”
So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).
X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x
And when solved, it has to equal 105.
So solve from here.
Combine like terms.
6x-9=105
Isolate
6x=114
x= 19
First evening is 9 less then 19, so 10.
The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76
1st night = 10
2nd night= 19 calls
Thrid night= 76 calls
