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Margarita [4]
3 years ago
5

What is 70% of $14.99?

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0
<span>$10.49 is 70% of $14.99.
</span>
Aleksandr [31]3 years ago
6 0
I pretty sure it's 10.49
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What does the graph look like
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3 years ago
Khan academy need help with this
rewona [7]

Step-by-step explanation:

6 * 1 = 6

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8 0
3 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the
Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of .

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is \pi = 0.5

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}

0.001\sqrt{n} = 2.327*0.5

\sqrt{n} = \frac{2.327*0.5}{0.001}

(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}

n = 1353732.25

Rounding up

A sample size of at least 1,353,733 is required.

5 0
4 years ago
Plz help i will give brainly!!! ignore the one i choose.
frosja888 [35]
Right triangle can be rotated to create a cone!
3 0
3 years ago
How to solve 8,725+w=10,619
tigry1 [53]
You subtract 8,725 to the other side so the problem would be w=10,619-8,725 and the answer would be W=1,894
3 0
4 years ago
Read 2 more answers
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