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3 years ago

What is 4+9+8+6+5+44+88+90+78

Mathematics

2 answers:

klasskru [66]3 years ago

8 0

4+9+8+6+5+44+88+90+78=332

DIA [1.3K]3 years ago

5 0

Step-by-step explanation:

4+9+8+6+5+44+88+90+78= 332

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3 years ago

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Identify (from the graph) the coordinates of the vertex: (4, 3). That +4 tells us that the vertex of the basic function y = |x| has been translated 4 units to the right; that +3 tells us that the vertex has also been translated 3 units up. Consider y = |x-a| + b. Here, b = +3 and a=+4. Thus, the correct function is f(x) = |x - 4| + 3.

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3 years ago

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3 years ago

In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti

elena-14-01-66 [18.8K]

Answer:

y = 0.3035 + 0.0082x

0.6315 mm

x = 23.9634 °C

Step-by-step explanation:

a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.

We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

$\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}$

Replacing the values in our formula (we will round at the end of the calculations)

$\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476$

the Y-intercept b is computed with the formula

$\bf b=\bar y-m\bar x$

therefore we have

$\bf b=0.5188-0.008169476*26.36=0.303452613$

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.

We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

Here, we replace y with 0.5 and solve for x

0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

x = 23.9634 °C

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4 years ago